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3 years ago

7

Richard took a trip from Montreal to Vancouver, a distance of 2,937.67 miles. John went from Chicago to Denver, a distance of 1,

014.9 miles. Richard went how much farther than John?

1 answer:

Radda [10]3 years ago

4 0

use photomath it helps a lot

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oee [108]

Yes they are equal they both have a side that is 25 degrees

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3 years ago

Sarah has 4 cousins. Melanie has 7 times as many cousins as Sarah. How many Cousins dose Melanie have?

Lina20 [59]

Answer:

Melanie has 28 cousins.

Step-by-step explanation:

4 x 7 = 28

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

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2 years ago

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Scores of two school basketball teams are recorded. The mean of Team A is 68. The mean of Team B is 67. What conclusion can you

Leto [7]

The conclusions that can be drawn are 3, two of a direct type and the other of an indirect type.

The direct ones are the values. Team A has an average of 68 points per game, which means that it has a good point average and, in the same way, team B, which has an average of 67, which is still a good point average per game.

The hint is the comparison of both teams, and that is that team A is one point above team B, which in terms of points per game makes them better.

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2 years ago

Use these clues to guess the mystery number. It is an odd number. It is greater than 142. It is less than 156. Rounded to the ne

Marianna [84]

Could be 154. 154 rounded to nearest ten= 150, rounded to nearest 100= 200

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3 years ago

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A national study report indicated that 20.9% of Americans were identified as having medical bill financial issues. What if a ne

Alenkasestr [34]

Answer:

The p-value for this test is 0.22065.

Step-by-step explanation:

We are given that a national study report indicated that 20.9% of Americans were identified as having medical bill financial issues.

A news organization randomly sampled 400 Americans from 10 cities and found that 90 reported having such difficulty.

<u><em>Let p = proportion of Americans who were identified as having medical bill financial issues in 10 cities.</em></u>

SO, Null Hypothesis, $H_0$ : p $\leq$ 20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is less than or equal to 20.9%}

Alternate Hypothesis, $H_A$ : p > 20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is more than 20.9% and is more severe}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 400 Americans from 10 cities who were found having such difficulty = $\frac{90}{400}$ = 0.225 or 22.5%

n = sample of Americans = 400

So, <u><em>test statistics</em></u> = $\frac{0.225-0.209}{{\sqrt{\frac{0.225(1-0.225)}{400} } } } }$

= 0.77

<u></u>

<u>Now, P-value of the test statistics is given by the following formula;</u>

P-value = P(Z > 0.77) = 1 - P(Z $\leq$ 0.77)

= 1 - 0.77935 = 0.22065

5 0

3 years ago