Answer:
I'm sorry but i don't know, but I do know the answer is <em>NOT B</em>
Step-by-step explanation:
Olivia's sample space consists of 36 pairs. Three (3) of them give a total of 10: (4, 6), (5, 5), (6, 4).
The probability of getting a total of 10 is 3/36 = 1/12.
Answer:
The phase shift:
1 unit to the right and 1 unit up
Step-by-step explanation:
∵ y = 1 + sin2(x - 1)
∴ y = 1 + sin(2x - 2)
∵ y = Sin(Bx - C) + D
∵ The vertical shift is D
∴ The horizontal shift is -C/B
∴ The vertical shift is 1 unit up
∴ The horizontal shift is --2/2 = 1 ⇒ 1 unite to the right
To solve an equation or inequality, you can add the same value to both sides of the expression. Here, it is convenient to choose that value to be the opposite of the constant (+15) added to y, so that constant is replaced by zero.
y + 15 - 15 < 3 - 15 . . . . . we have added -15 to both sides
y < -12 . . . . . . . . . . . . . . . the result of simplifying. This is your solution.
Number 19 you are comparing one measurement to another. Since it says 1/2 inch equals 4 ft, we want to find out how many more inches are needed if the given scale was 2/3 = 4 ft. Now lets find a common denominator for both scales stated in inches. We have 2/3 inch and 1/2 inch. Our denominator are the bottom parts of the fraction where we need to find a common factor for the denominator so we can add or subtract fractions. We have a 3 and a 2. You may always use the multiplication between two denominators to find a common factor such as 3 times 2 which equals 6 for both denominators. Now we multiplied the 3 by 2 to get 6 so the top part (numerator needs to be multiplied the the 2 because we changed the bottom part by 2 as well. You should notice that when you reduce your fraction now 4/6 is 2/3. Just a self check example there. As for 1/2 we multiplied a 3 to get 6 for the denominator so we need to multiply the numerator by 3 as well. You now should have 4/6 and 3/6. Since the question asks for how many more inches we need to subtract 4/6 from 3/6 and we get 1/6 inch for our answer.
