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2 years ago

PLEASE HELP IM FAILING MATH

Mathematics

1 answer:

Mamont248 [21]2 years ago

4 0

Answer:

$5,665

Step-by-step explanation:

First, you multiply 5,500 times 3 to get 16,500, and then divide by 100 to get 165. That is how much she earned over the past three years, but it is NOT her new account balance, because you have to add 5,500 and 165, which you would get a final sum of $5,665. I hope this helps :)

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Can someone plz help me dont know the awnser

Bumek [7]

The area of the right triangle = $\frac{1}{2}bh$

b = base = SV = 12.3
h = hight = HL = 24.6
A = area
$\frac{1}{2}bh = A$
$\frac{1}{2}(12.3)(24.6) = 151.29$

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3 years ago

Is there enough information to prove each quadrilateral is a parallelogram? Explain.

omeli [17]

Answer:

1. yes

2, no

3. yes

4. yes

Step-by-step explanation:

1. yes

If both sets of opposite sides are congruent, the quadrilateral is a parallelogram.

2. no

We know two side lengths. We know nothing about the other 2 sides and also nothing about all 4 angles.

3. yes

The missing angle must be 102°. With both pairs of opposite angles congruent, it must be a parallelogram.

4. yes

With both pairs of opposite angles congruent, it must be a parallelogram.

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2 years ago

What is the equivalent of <br>2/3x -9 - 2x + 2 = 1 after combining like terms?

elena-s [515]

Answer:

Step-by-step explanation:

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3 years ago

What three ratios are equivalent to 5 to 2

Hoochie [10]

Answer:

10:4, 15:6, 20:8

hope that helps.

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3 years ago

Someone please help me!!!!!

Katarina [22]

1. Answer (D). By the law of sines, we have $\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}$ in any $\triangle ABC.$

2. Answer (C). The law of cosines, $c^2=a^2+b^2-2ab\cos C,$ accepts up to three sides and an angle as an input.

3. Answer (D). Although this triangle is right, we are not given enough information to uniquely determine its sides and angles - here, we need either one more side or one more angle.

4. Answer (D). Don't get tripped up by answer choice (C) - this is just a rearrangement of the statement of the law of cosines. In choice (D), the signs of $a^2$ and $2ab\cos C$ are reversed.

5. Answer (B). By the law of sines, we have $\frac{5}{\sin 40^\circ}=\frac{3}{\sin\theta}.$ Solving gives $\theta\approx \boxed{23^\circ},157^\circ.$ Note that this is the <em>ambiguous (SSA) case</em> of the law of sines, where the given measures could specify one triangle, two triangles, or none at all!

6. Answer (A). Since we know all three sides and none of the angles, starting with the law of sines will not help, so we begin with the law of cosines to find one angle; from there, we can use the law of sines to find the remaining angles.

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3 years ago