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3 years ago

8

The distance between two points is 6√5. One endpoint is (4,−3). It is known that the y-coordinate of the other endpoint is 7.

1 answer:

boyakko [2]3 years ago

8 0

(2,-4)snhfbdjsnsndusma

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What is the quotient of k

makvit [3.9K]

Do you have a picture?

6 0

3 years ago

a square dance set requires 4 couples 8 dancers with each couple standing on one side of a square. There are 250 people at a squ

sveta [45]

Given:

1 set requires 4 couples 8 dancers.

Total number of people at a square dance = 250.

To find:

The greatest number of sets possible at the dance.

Solution:

We have,

Total people = 250

1 set = 8 people.

$\text{Number of possible sets}=\dfrac{\text{Total people}}{\text{People required for 1 set}}$

$\text{Number of possible sets}=\dfrac{250}{8}$

$\text{Number of possible sets}=31.25$

Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

$\text{Number of possible sets}\approx 31$

Therefore, the number of possible sets at the dance is 31.

7 0

3 years ago

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago

The fox population in a certain region has a continuous growth rate of 6 percent per year. It is estimated that the population i

riadik2000 [5.3K]

Answer

a)

$P(t) = 19100. e^{0.06t}$

b) P(8) =30866

Step-by-step explanation

Use formula:

$P(t) = P. e^{rt}$

a)

Here, P = 19100

r = 6% = 0.06

$P(t) = 19100. e^{0.06t}$

b) t = 2008 - 2000 = 8

$P(8) = 19100. e^{0.06\times 8}$

$P(8) = 19100. e^{0.48}$

$P(8) = 19100\times 1.616\\\\P(8) = 30,865.6\\\\P(8) \approx 30,866$

6 0

3 years ago

A sporting goods store charges $30 for 12 cans of tennis balls and $45 for two boxes of golf balls. A coach orders100 cans of te

aliya0001 [1]

362.50 for tennis and golf balls.
To find the answer divide the dollar amount by how many cans or boxes each cost then multiply that answer by the total amount purchased.
Golf balls
45/2=22.50 each box
22.5*5=112.50 total
Tennis balls
30/12=2.50 each can
2.50*100 = 250.00
add the dollar amounts together
112.50+250.00 =362.50

3 0

4 years ago