Answer:
D
Step-by-step explanation:
The hypotenuse squared is equal to the sum of the legs squared in a right triangle.
∴ c² = a² + b² (Pythagorean’s Theorem)
c² = 3.4² + 6.7² (substitute the given values for a & b)
c² = 11.56 + 44.89 (square both right hand terms)
c² = 56.45 (add the right hand side values)
c = √56.45 (square root of both sides)
c ≈ 7.5 to the nearest tenth QED
Addition of 6q + 1 and q + 11 is 7q + 12
<em><u>Solution:</u></em>
Given that, we have to add the given two expressions
<em><u>Given expressions are:</u></em>
6q + 1 and q + 11
We have to add both the expressions
Addition of 6q + 1 and q + 11 = 6q + 1 + q + 11
Add the coefficients of same variable. Here "q" is present in two terms
Therefore, add 6q and q
Similarly, add the constants 1 and 11
<em><u>Thus finally addition is done as:</u></em>

Thus addition of 6q + 1 and q + 11 is 7q + 12
Answer:
I think 12 but I gave it a shot
<h3>
Answer: 35 degrees Celsius </h3>
start at 40 on the number line. Move 5 units to the left to arrive at 35
40-5 = 35
Or you can have a vertical number line. Start at 40 and move down 5 units to arrive at 35.