Find the 13th term of the arithmetic sequence -2x+8, 4x+2, 10x-4, ...
1 answer:
here's the solution,
<em><u>First term</u></em> (a) :
=》 -2x + 8
<em><u>Common difference </u></em> (d) :
=》4x + 2 - (-2x + 8)
=》4x + 2 + 2x - 8
=》6x - 6
<u>12th term</u> :
=》a + (n - 1)d
=》-2x + 8 + (12 - 1) × (6x - 6)
=》-2x + 8 + (11) × (6x - 6)
=》-2x + 8 + 66x - 66
=》64x - 58
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