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PilotLPTM [1.2K]
3 years ago
14

PLEASE HELP 20 POINTS SHOW ALL WORK

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

Answer:

Steps below

Step-by-step explanation:

8) x = y²/2           2rcosΘ = r²sin²Θ      2cosΘ = rsin²Θ

   r = 2cosΘ/sin²Θ = 2cotΘcscΘ

9) (x+2)²+y²=4     y= rsinΘ     x=rcosΘ

   (rcosΘ+2)²+y²sin²Θ = 4

   r²cos²Θ+4rcosΘ+4+y²sin²Θ=4

   r²(sin²Θ+cos²Θ)+4rcosΘ=0

   r²+4rcosΘ=0            r+4cosΘ=0

   r = - 4cosΘ

10) r = 2sinΘ         r=2* y/r           r²=2y       x²+y²=2y

     x² + (y²-2y+4) = 4          x²+(y-2)² = 4

11) r = 3tanΘsecΘ = 3* (y/x) * (r/x)

   1 =3y/x²

   x² = 3y        3y = x²

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Of the cars sold during the month of July, 89 had air conditioning, 99 had an automatic transmission, and 74 had power steering.
DedPeter [7]

Answer:

There are a total of 23 cars with air conditioning and automatic transmission but not power steering

Step-by-step explanation:

Let A be the cars that have Air conditioning, B the cars that have Automatic transmission and C the cars that have pwoer Steering. Lets denote |D| the cardinality of a set D.

Remember that for 2 sets E and F, we have that

|E \cup F| = |E| + |F| - |E \cap F|

Also,

|E| = |E ∩F| + |E∩F^c|

We now alredy the following:

|A| = 89

|B| = 99

|C| = 74

|A \cap B \cap C| = 5

|(A \cup B \cup C)^c| = 24

|A \ (B U C)| = 24 (This is A minus B and C, in other words, cars that only have Air conditioning).

|B \ (AUC)| = 65

|C \ (AUB)| = 26

|B \cap C| = 11

We want to know |(A∩B) \ C|. Lets calculate it by taking the information given and deducting more things

For example:

99 = |B| = |B ∩ C| + |B∩C^c| = 11 + |B∩C^c|

Therefore, |B∩C^c| = 99-11 = 88

And |A ∩ B ∩ C^c| = |B∩C^c| - |B∩C^c∩A^c| = |B∩C^c| - |B \ (AUC)| = 88-65 = 23.

This means that the amount of cars that have both transmission and air conditioning but now power steering is 23.

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