Apply the associative property of multiplication to rewrite the expression and simplify -4(9b)

Write an expression so that the product of a whole number and a decimal is 0.32.

lord [1]

A possible answer would be 32*0.01

7 0

3 years ago

When the new principal on a loan is $79,946.13 and the interest rate is 8 percent, the monthly payment is $587.20. Find the inte

lesya [120]

9514 1404 393

Answer:

to interest: $532.97
to principal: $54.23
new balance: $79,891.90

Step-by-step explanation:

The interest is found by multiplying the monthly rate by the balance on the loan. For the first month, the balance is the loan amount.

$79,946.13 × 0.08 ×(1/12) . . . . . one month = 1/12 year

= $532.97

The interest amount in the first payment is $532.97.

__

The amount of the first payment that goes to principal is what is left after the interest is paid:

$587.20 -532.97 = $54.23 . . . amount to principal

__

The new balance is the previous balance less the amount to principal:

$79,946.13 -54.23 = $79,891.90 . . . new balance

7 0

3 years ago

Consider the expression. What is the result of applying the quotient of powers rule to the expression?

fenix001 [56]

Answer:

Let us consider the expression:

$\frac{a^5\cdot b^6}{a^2\cdot b^9}$ (1)

Now, the quotient of power rules says that the numbers that have same base can be find by subtracting if powers are with same sign

And adding if powers are with opposite sign.

We will solve equation (1) by this quotient of power rule.

So, it can be rewritten as:

$a^{5-2}\cdot b^{6-9}$

$\Rightarrow a^{3}\cdot b^{-3}$ .

8 0

3 years ago

Read 2 more answers

What is the equation of the line in point-slope form?

Alisiya [41]

Answer: y=-2x+2/4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago