Because C is the centroid, therefore:
Segments PZ = ZR; RY = YQ; QX = XP<span>
<span>A.
If CY = 10, then</span></span>
PC = 2*CY = 20<span>
PY = PC + CY = 20 + 10 = 30
Answer: PC = 20</span> PY = 30
B.
If QC = 10, then
ZC = QC/2 = 5<span>
ZQ = ZC + QC = 5 + 10 = 15
Answer: ZC = 5</span> ZQ = 15
<span>C.
<span>If PX = 20
Because the median RX bisects side PQ, therefore PX = QX = 20
PQ = PX + QX = 40
Answer: <span>PQ = 40</span></span></span>
Answer:
positive x
Step-by-step explanation:
Answer:
Step-by-step explanation:
5 spaces 2/5 0.22
240 inches cut into 2 equal pieces is just taking half of the wire.
Making the two pieces of wire 120 inches.
If you bend one 120 inch wire into a square, that means that each side equals 30 inches. (A square has 4 sides. 120/4 = 30)
An area of a square is length times width, which the length equals 30 and width equal to thirty. 30 * 30 = 900. square inches.
120 wire bent into a triangle makes each side equal to 40. 120/3=40. The area of an equilateral triangle is height times width. The width is just one of the sides (40 inches) but the height needs some geometry. To find the height you need to use either 30 times sin(60) or 30 times cos(30), both are equal. To be clear, I will leave the height as 30sin(60). The area will be equal to
![40*30sin(60)](https://tex.z-dn.net/?f=40%2A30sin%2860%29)
which can be simply written as 1200sin(60).
So the sum of both areas is
Answer:
y=x-4
Step-by-step explanation:
What you are looking for is also known as the slant asymptote. The slant asymptote occurs when the degree of the numerator is one degree more than the denominator which is what you have.
So to find the slant asymptote we can use polynomial division.
We have a choice to use synthetic division here because the denominator is linear.
-1 goes on the outside because we are dividing by (x+1).
-1 | 1 -3 -4
| -1 4
|----------------------
1 -4 0
The asymptote is the quotient part which is y=x-4.
So answer is y=x-4.