Function 1 has a maximum at y = 1
Now we need to find the maximum of Function 2 by completing the square:
-x^2 + 2x - 3
= -(x^2 - 2x) - 3
= -(x - 1)^2 +1 - 3
= -(x - 1)^2 - 2
Therefor the turning point is at (1, -2) and the maximum is at y = -2
-2 < 1, therefor Function 1 has the larger maximum
Slope formula: y₂ - y₁
-----------
x₂ - x₁
-9 - (-1) -8 -4
--------------- = -------- = --------
0 - (-6) 6 3
I'll help you in the comments of this questions. need time to work it out.
F + 2b = 92
3b + 4f = 212
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You didn’t say you need them solved, but just in case:
f = 92 -2b
3b + 4(92-2b) = 212
3b + 368 -8b = 212
-5b = -156
b = 31.20
f + 2(31.20) = 92
f + 62.4 = 92
f = 29.60
3(31.2) + 4(29.6) = 93.6 + 118.4 = 212
Step-by-step explanation:
let's think about it logically :
|x| can only be positive, from 0 to +infinity.
but the second part "- 4" will bring the result for small x values into the negative realm.
x = 0 gives us f(x) = -4.
x = 4 gives us f(x) = 0
x = -4 gives us f(x) = 0
so, if is the 3rd graph (bottom left).