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Pavlova-9 [17]
3 years ago
8

Need help asap! Show work if you can, it’s completely ok if you don’t tho

Mathematics
1 answer:
Savatey [412]3 years ago
8 0
Its A) -67
plug the m and n values into the function and solve using pemdas.
5(-7)-2(-7+3)^2
-35-2(-4)^2
-35-2(16)
-35-32
-67
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Evaluate f(-2) = -3x² - 2x
Delvig [45]

Answer:

-2F=7x

Step-by-step explanation:

F*-2= -2F       3x*3x=9x

-2F=9x-2x

<u>-2F=7x</u>

8 0
2 years ago
One of two complementary angles is 12 degrees greater than the other. Find the measure of the larger angle.
stiks02 [169]

Answer:

39,51

Step-by-step explanation:

Complementary angles add to 90 degrees

Let one angle be x

The other angle is x+12

x+ x+12 = 90

Combine like terms

2x+12 = 90

Subtract 12 from each side

2x+12-12 = 90-12

2x = 78

Divide each side by 2

2x/2 = 78/2

x =39

The other angle is 39+12 =51

8 0
3 years ago
Identify the reason that justifies each statement.
Ostrovityanka [42]

Answer:

Vertical angles

Step-by-step explanation:

The diagram shows two straight line intersecting to form vertical angles. One of such pair of vertical angles formed is <1 and <2.

Vertical angles are congruent to each other. Therefore, the reason why <1 ≅ <2 is because they are vertical angles or vertical angles pair.

4 0
3 years ago
Use the quadratic formula to solve for the roots in the following equation. 4x 2 + 5x + 2 = 2x 2 + 7x – 1
Natali5045456 [20]

Answer:

So, The roots are x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}

Step-by-step explanation:

4x^2 + 5x + 2 = 2x^2 + 7x - 1

We need to solve the equation to find the roots using quadratic formula.

The quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Rearranging the above equation:

4x^2 -2x^2+ 5x-7x + 2+1 =0

2x^2 -2x + 3 =0

Where a =2 , b=-2 and c =3 Putting values in quadratic equation and solving:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(2)(3)}}{2(2)}\\x=\frac{2\pm\sqrt{4-24}}{4}\\x=\frac{2\pm\sqrt{-20}}{4}\\\sqrt{-20} \,\,can\,\,be\,\, written\,\, as\,\, 2\sqrt{-5}\\ x=\frac{2\pm2\sqrt{-5}}{4}\\x=\frac{2+2\sqrt{-5}}{4} \,\, and \,\, x=\frac{2-2\sqrt{-5}}{4}\\x=\frac{2(1+\sqrt{-5})}{4} \,\, and \,\, x=\frac{2(1-\sqrt{-5})}{4}\\ x=\frac{1+\sqrt{-5}}{2} \,\, and \,\, x=\frac{1-\sqrt{-5}}{2}\\As \,\,we\,\, know\,\, \sqrt{-1} = i \\

x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}

So, The roots are x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}

6 0
3 years ago
Write the equation of the line that passes through the given points.<br> (0,4) and (5,10)
seropon [69]

Answer:

y = \frac{6}{5}x + 4

Step-by-step explanation:

Use the slope formula and slope-intercept form y=mx+b to find the equation.

5 0
3 years ago
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