All categories

3 years ago

Which step could be used to solve x + 3.6 = negative 1.7 for x in one step? Select two options.

Mathematics

2 answers:

Whitepunk [10]3 years ago

7 0

Subtract 3.6 from both sides. You would be left with x=-5.3

-Dominant- [34]3 years ago

4 0

Answer:

option 2 and 5 are the correct ones. sorry if im wrong

Step-by-step explanation:

You might be interested in

he price of a pair of shoes increases from $68 to $77. What is the percent increase to the nearest percent?

tekilochka [14]

Answer:

an increase of 12%

Step-by-step explanation:

68 divided by 77 is 0.88 approximately

100-88 is 12

Tip:

do this for increase and decrease in percentage question

divide small number by big number, and subtract the quotient from 100

8 0

3 years ago

Read 2 more answers

The cafeteria wants to buy 4,500 new forks. If each package contains 90 forks, how many packages should the cafeteria buy?

nikdorinn [45]

Answer:

Step-by-step explanation:

4,500÷90=50

and to check

90×50=4500

4 0

3 years ago

Solve using long division <br> Please

madreJ [45]

1. $Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}$

$Steps:$

$\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}$

$\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}$

$\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}$

$\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}$

$\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}$

2. $Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}$

$Steps:$

$\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}$

$\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}$

$\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

4 0

3 years ago

Steven wants to buy a $565 bicycle. Steven has no money saved, but will be able to deposit $30 into a savings account when he re

White raven [17]

535 i think thats wat it is

4 0

3 years ago

A rectangle has length 4 inches and width 2 inches. If the length and width of the rectangle are each reduced by 50 percent, by

exis [7]

Answer: 25%

Step-by-step explanation:

Given: A rectangle has length 4 inches and width 2 inches.

Area = Length x width

= 4 inches x 2 inches

= 8 square inches

If length is reduced by 50% , then length $=0.5\times4=2\text{ inches}$

If width is reduced by 50% , then length $=0.5\times2=1\text{ inch}$

Reduced area = (reduced length) x (reduced width)

= 2 inches x 1 inch

= 2 square inches

The percentage of the area of the rectangle be reduced :-

$\dfrac{\text{Reduced area}}{\text{Original area}}\times100 \\\\=\dfrac{2}{8}\times100\% \\\\=25\%$

Hence, the percent of the area of the rectangle be reduced = 25%

6 0

3 years ago