The area of a trapezoid is
A = (1/2) h (b1 + b2)
where
h is the height
b1 is length of base 1
b2 is the length of base 2
We are given with the area and assuming that the trapezoid is isosceles, the length of base 1 is
b1 = 4 ft
If the height of the trapezoid is 4.5 feet, it ensures that the shed will fit inside the trapezoid patch of land. Therefore, the height of the trapezoid is 4.5 feet.
Answer:
the answer for a is 0.045
Answer:
On the graph you can read that at x = 22, f(x) ≈ 12, and at x = 26 f(x) ≈ 7.
So, an approximate rate of change from x = 22 to x = 26 is given by the equation below:
change on f(x) 7 - 12
average rate of change = --------------------- = ----------- = -5/4
change of x 26 - 22
That rate represents that the ball fell about 5 ft per 4 ft in that interval.
Step-by-step explanation:
Answer:
Yes, the following equation is a quadratic function in vertex form
Step-by-step explanation:
we know that
The <u>quadratic function</u> of the vertical parabola into <u>vertex form</u> is equal to
where
(h,k) is the vertex of the parabola
If the <u>coefficient</u> a is > 0 ----> the parabola open upward (vertex is a minimum)
If the coefficient a is < 0 ----> the parabola open downward (vertex is a maximum)
in this problem we have
The <u>squared term</u> contain the x-coordinate of the vertex
The <u>constant term</u> is the y-coordinate of the vertex
The vertex is the point (2,6)
The coefficient is equal to
----> open upward (vertex is a minimum)
Each pencil weighs 4 grams so the answer is B: 4