Answer:
Bohr o saka mi ad ha piebald webs ldb
Explanation:
<h3>
Answer:</h3>
1.1 × 10²² atoms Au
<h3>
General Formulas and Concepts:</h3>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.7 g Au
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Au - 196.97 g/mol
<u>Step 3: Convert</u>
<u />
= 1.13121 × 10²² atoms Au
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules and round.</em>
1.13121 × 10²² atoms Au ≈ 1.1 × 10²² atoms Au
Answer:
D. -1882J
Explanation:
We can solve the energy released in a chemical reaction in an aqueous medium using the equation:
Q = -m*C*ΔT
<em>Where Q is energy (In J),</em>
<em>m is mass of water (45.00g)</em>
<em>C is specific heat of water (4.184J/g°C)</em>
<em>And ΔT is change in temperature (25.00°C - 15.00°C = 10.00°C)</em>
<em />
Replacing:
Q = -45.00*4.184J/g°C*10.00°C
Q = -1882J
Right answer is:
<h3>D. -1882J</h3>
<em />
The appropriate response is high. The best approach to consider it is those molecules have more vitality than the normal and it is unequivocally those higher enthusiastic ones that have enough vitality to break the intra-molecular forces and leave. By the way this is the reason when we sweat we chill off - the most enthusiastic molecules vanish diverting warmth.
Answer:
10.69g/cm^3 or 0.0106kg/m^3
Explanation:
10.69 g/cm^3: I wrote this answer because your question doesn't mention whether volume is in cm^3 or m^3. If its in cm^3, then this is your answer.
0.0106kg/m^3: This might also be the answer if the volume is in m^3. If it is in m^3 then you have convert grams into kilograms.
So technically since you questions incomplete, the equation for measuring density is P= m/v
P= rho (density)
m= mass
v= volume
Hope it helps- Z