Write the dissociation equation for NH4OH.
1 answer:
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Answer:
Methane is a covalent bond. Methane is a chemical compound from the bonding one carbon atom and for hydrogen atoms. Although electronegativity increases as you go right of the periodic table, hydrogen has an electronegativity of 2.20. Chlorine has an electronegativity of 2.55. There difference in electron negativity (0.34). Therefore it is a non polar compound. If there difference was much greater, than they would form a ionic bond. Alkali metals tend to form the most ionic bond, but although hyrdogen is placed with them, it has a higher electronegativity so hydrogen is an exception.
Carbon has 4 valence electrons so it will want to gain 4 more electrons to become stable (Octet rule). Hydrogen has 1 valence electron, so it will want to lose it to become stable. Therefore, one carbon atom takes 1 electrons from 4 hydrogen atoms.
Answer:
1, 2, and 3 are true.
Explanation:
The Henderson-Hasselbalch equation is:
pH = pka + log₁₀
- If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined. <em>TRUE</em>
pH = pka + log₁₀
If you know pH and pka:
10^(pH-pka) =
The ratio will be: 10^(pH-pka)
- At pH = pKa for an acid, [conjugate base] = [acid] in solution. <em>TRUE</em>
pH = pka + log₁₀
0 = log₁₀
10^0 =
1 =
As ratio is 1, [conjugate base] = [acid] in solution.
- At pH >> pKa for an acid, the acid will be mostly ionized. <em>TRUE</em>
pH = pka + log₁₀
If pH >> pKa, 10^(pH-pka) will be >> 1, that means that you have more [A⁻] than [HA]
- At pH << pKa for an acid, the acid will be mostly ionized. <em>FALSE</em>
pH = pka + log₁₀
If pH << pKa, 10^(pH-pka) will be << 1, that means that you have more [HA] than [A⁻]
I hope it helps!