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VMariaS [17]
3 years ago
9

THE ASTHENOSPHERE IS CONSIDERED TO BE A SOFT SOLID.True or False

Chemistry
2 answers:
asambeis [7]3 years ago
8 0
Your answer is false
const2013 [10]3 years ago
6 0
The answer would be false
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What part of cellular respiration is affected by arsenic
LenaWriter [7]

Answer:

It effects all of the cellular respiration process

Explanation:

It inhibits the Glycolysis. It replaces the phosphate groups that is needed for making Pyruvate and ATP.

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4 years ago
How are the carbon, oxygen, and nitrogen cycles vital to sustaining life on Earth?. a.. Carbon, oxygen, and nitrogen are vital c
kumpel [21]

The correct answer is (D)


All the above are reasons the carbon , oxygen, and nitrogen cycles are vital to life on earth.


The explanation:


because :


1) Carbon, oxygen, and nitrogen are vital components of life on Earth.


2) The carbon, oxygen, and nitrogen cycles allow vital elements to return to usable form by organisms.


3)The carbon, oxygen, and nitrogen cycles are an important interface between biotic and abiotic factors


4) They are all biogeochemical cycles.


5) They all involve an interaction between living and nonliving elements.

6)They are all part of the Earth system.

5 0
3 years ago
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HELPPPPPP<br><br> is this <br> 1:conduction<br> 2:radiation<br> 3:convection
qaws [65]

Answer:

Radiation

Explanation:

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3 0
3 years ago
The modern synthesis combined the concepts of _______ and evolution.
aalyn [17]
Answer:

Molecular Evidence.
4 0
3 years ago
What are the concentrations of h3o+ and oh− in tomatoes that have a ph of 4.10?
IRINA_888 [86]

Answer : The concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

Solution : Given,

pH = 4.10

pH : pH is defined as the negative logarithm of hydronium ion concentration.

Formula used : pH=-log[H_3O^+]

First we have to calculate the hydronium ion concentration by using pH formula.

4.10=-log[H_3O^+]

[H_3O^+]=antilog(-4.10)

[H_3O^+]=7.94\times 10^{-5}

Now we have to calculate the pOH.

As we know, pH+pOH=14

4.10+pOH=14

pOH=9.9

Now we have to calculate the hydroxide ion concentration.

pOH=-log[OH^-]

9.9=-log[OH^-]

[OH^-]=antilog(-9.9)

[OH^-]=1.258\times 10^{-10}

Therefore, the concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

5 0
3 years ago
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