Explanation:
because in the right side there is 2 hydrogen( H) and 2 chloride (Cl) to balace them we have to replace 2.
41.6g/cm3 would be the density of the bread
Answer:
Number of moles of oxygen = 0.037 mol
Explanation:
Given data:
Total pressure = 98.5 KPa
Partial pressure of nitrogen = 22.0 KPa
Partial pressure of argon = 50.0 KPa
Volume = 3.5 L
Temperature = 25°C (25+273= 298K)
Number of moles of oxygen = ?
Solution:
Total pressure = P(N₂) + P(O₂) + P(Ar)
98.5 KPa = 22.0 KPa +P(O₂) + 50.0 KPa
98.5 KPa = 72.0 KPa +P(O₂)
P(O₂) = 98.5 KPa - 72.0 KPa
P(O₂) = 26.5 KPa
KPa to atm:
26.5 KPa/ 101 = 0.262 atm
Number of moles of oxygen:
PV = nRT
n = PV/RT
n = 0.262 atm × 3.5 L / 0.0821 atm.L/mol.K × 298 K
n = 0.917atm.L /24.47atm.L/ mol
n = 0.037 mol
Answer:
Option 4
Explanation:
In water molecule, oxygen has -2 charge on it while the hydrogen has +1 charge and one atom of oxygen combines with two hydrogen atoms. A hydrogen need only two electrons to complete its octet (one electron is its own the second electron is shared by oxygen) and a oxygen needs 8 electrons (It has six of its own and two are shared by two hydrogen atom).
Hence, option 4 is correct
Hey there! Hello!
Not sure if you still need the answer to this question, but I'd love to help out if you do.
So, the way to balance this equation is pretty simple. First, you need to keep in mind that molecules of hydrogen and oxygen do not come in single molecules, but in bonded pairs, represented by H2 and O2.

But, that's incorrect. The combination of 2 hydrogen molecules with 1 oxygen molecule yields water, but that leaves one oxygen molecule leftover. When broken down, this is how many of each molecule is on each side of the previously stated equation:
Left:
H: 2
O: 2
Right:
H: 2
O: 1
So we have to multiply H2O on the right side by 2 in order to get this:

Left:
H: 2
O: 2
Right:
H: 4
O: 2
The last step is to multiply H2 on the left by two to make it match up with the right side, balancing the equation:

Left:
H: 4
O: 2
Right:
H: 4
O: 2
That makes our equation balanced! I hope this helped you out, feel free to ask any additional questions if you need further clarification. :-)