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seropon [69]
3 years ago
9

44.90 g of reactants are placed in a beaker

Chemistry
1 answer:
sergiy2304 [10]3 years ago
7 0

Answer:

D. -1882J

Explanation:

We can solve the energy released in a chemical reaction in an aqueous medium using the equation:

Q = -m*C*ΔT

<em>Where Q is energy (In J),</em>

<em>m is mass of water (45.00g)</em>

<em>C is specific heat of water (4.184J/g°C)</em>

<em>And ΔT is change in temperature (25.00°C - 15.00°C = 10.00°C)</em>

<em />

Replacing:

Q = -45.00*4.184J/g°C*10.00°C

Q = -1882J

Right answer is:

<h3>D. -1882J</h3>

<em />

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wood burning and cookies baking

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Why did humans overhunt the Caribbean monk seal to extinction?
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A chemist titrates 0.200 M NaOH, strong base, with 50.00 ML of 0.100 M HCI, strong acid. How many mL of NaOH will be required to
nalin [4]

Answer:

25 mL of NaOH

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of the base, NaOH (n₆) = 1

Finally, we shall determine the volume of NaOH required for the reaction. This can be obtained as follow:

Molarity of the base, NaOH (M₆) = 0.2 M

Molarity of the acid, HCl (Mₐ) = 0.1 M

Volume of the acid, HCl (Vₐ) = 50 mL

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of the base, NaOH (n₆) = 1

Volume of the base, NaOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ / n₆

0.1 × 50 / 0.2 × V₆ = 1

5 / 0.2 × V₆ = 1

Cross multiply

5 = 0.2 × V₆

Divide both side by 0.2

V₆ = 5/0.2

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Thus, 25 mL of NaOH is needed for the reaction

8 0
3 years ago
Classify each of these reactions. Ba ( ClO 3 ) 2 ( s ) ⟶ BaCl 2 ( s ) + 3 O 2 ( g ) acid–base neutralization precipitation redox
Blababa [14]

Answer:

Ba(ClO₃)₂ (s) ⟶ BaCl₂(s) + 3O₂ (g)   REDOX

2 NaCl (aq) + K₂S (aq) ⟶ Na₂S (aq) + 2 KCl (aq)        NONE

CaO (s) + CO₂ (g) ⟶ CaCO₃(s) NONE

KOH (aq) + AgNO₃(aq) ⟶ KNO₃(aq) + AgOH (s)  PRECIPITATION

Ba (OH)₂(aq) + 2 HNO₂(aq) ⟶ Ba (NO₂)₂(aq) + 2 H₂O (l)  NEUTRALIZATION

Explanation:

Redox reaction involves the oxidation states. The oxidation state from an element decreases and the oxidation state from other element increases.

It is called redox because one element reduces and the other oxidizes.

Neutralization reaction occurs when an acid and a base react, to produce water an a determined salt.

Precipitation reaction can be produced when a solid is formed as the reactants react.

Ba(ClO₃)₂ (s) ⟶ BaCl₂(s) + 3O₂ (g)   REDOX

Cl changes the oxidation state from 5 to -1  (reduction)

O changes the oxidation state from -2 to 0 (oxidation)

2 NaCl (aq) + K₂S (aq) ⟶ Na₂S (aq) + 2 KCl (aq)        NONE

CaO (s) + CO₂ (g) ⟶ CaCO₃(s) NONE

KOH (aq) + AgNO₃(aq) ⟶ KNO₃(aq) + AgOH (s)  PRECIPITATION

Ba (OH)₂(aq) + 2 HNO₂( aq ) ⟶ Ba (NO₂)₂(aq) + 2 H₂O (l)  NEUTRALIZATION

3 0
3 years ago
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