Answer:
the fossils on some of the continents were in the same spots as fossils on other continents
Explanation:
tell me if i need to explain more. x
Answer:
is used to break reactant bonds and/or make new product bonds.
Explanation:
<em>The correct answer would be that </em><em>activation energy is used to break reactant bonds and/or make new product bonds</em><em>.</em>
The <u>activation energy is the minimum energy that must be overcome by the reactants in a reaction in other to become products</u>. In order for products to be formed, the bonds between reactants must be broken and new ones must be formed to arrive at the products. In other words, the activation energy can be seen as the energy required to break the bonds between reactants and form the bonds between products during the course of a reaction.
<em>Activation energy is required even in the presence of enzymes. The latter only catalyzes reactions by lowering the minimum energy required to break the bonds between reactants and form new ones between products</em>.
Answer : the hydrogen ion concentrations for pH = 7.35 and pH = 7.45 are 4.46 x 10⁻⁸ M and 3.54 x 10⁻⁸ M respectively.
When the pH of a solution is less than 7, the hydrogen ion concentration is higher and therefore the solution is acidic.
On the other hand, when the pH of a solution is greater than 7, hydroxide ion concentration is higher and the solution acts as a base.
The normal pH range of blood is given as 7.35 - 7.45 which is greater than 7. That means blood is slight basic in nature.
Let us find hydroxide ion concentration of blood.
![pOH = - log [OH-]](https://tex.z-dn.net/?f=pOH%20%3D%20-%20log%20%5BOH-%5D)
![[OH-] = 10^{-6.65}](https://tex.z-dn.net/?f=%5BOH-%5D%20%3D%2010%5E%7B-6.65%7D)
![[OH-] = 2.24 \times 10^{-7}](https://tex.z-dn.net/?f=%5BOH-%5D%20%3D%202.24%20%5Ctimes%2010%5E%7B-7%7D)
Ionic product of water is written as,
![[H+] [OH-] = 1 \times 10^{-14}](https://tex.z-dn.net/?f=%5BH%2B%5D%20%5BOH-%5D%20%3D%201%20%5Ctimes%2010%5E%7B-14%7D)
Let us plug in the calculated value of [OH-]
![[H+] = \frac{1 \times 10^{-14}}{2.24 \times 10^-7} = 4.46 \times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%20%5Cfrac%7B1%20%5Ctimes%2010%5E%7B-14%7D%7D%7B2.24%20%5Ctimes%2010%5E-7%7D%20%3D%204.46%20%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentration for pH = 7.35 is 4.46 x 10⁻⁸ M
Calculation of [H+] for pH = 7.45
pOH = 6.55
[OH-] = 2.82 x 10⁻⁷
![[H+] = \frac{1 \times 10^{-14}}{2.82 \times 10^-7} = 3.54 \times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%20%5Cfrac%7B1%20%5Ctimes%2010%5E%7B-14%7D%7D%7B2.82%20%5Ctimes%2010%5E-7%7D%20%3D%203.54%20%5Ctimes%2010%5E%7B-8%7D%20M)
Similarly, for pH = 7.45, we get hydrogen ion concentration of 3.54 x 10⁻⁸ M.
