Answer: 0.8 M
Explanation:
molarity = (moles of solute)/(liters of solution) = 1.25/1.5 = 0.8 M
Answer:
4.8 %
Explanation:
We are asked the concentration in % by mass, given the molarity of the solution and its density.
0.8 molar solution means that we have 0.80 moles of acetic acid in 1 liter of solution. If we convert the moles of acetic acid to grams, and the 1 liter solution to grams, since we are given the density of solution, we will have the values necessary to calculate the % by mass:
MW acetic acid = 60.0 g/mol
mass acetic acid (the solute) = 0.80 mol x 60 g / mol = 48.00 g
mass of solution = 1000 cm³ x 1.010 g/ cm³ (1l= 1000 cm³)
= 1010 g
% (by mass) = 48.00 g/ 1010 g x 100 = 4.8 %
Answer:
Maybe A)
Explanation:
Can you make me the Brainliest answer ?
Answer:
Mass = 25.08 g
Explanation:
Given data:
Volume of fluorine = 29.6 L
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Mass of fluorine = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm × 29.6 L / 0.0821 atm.L/ mol.K × 273.15 K
n = 1.32 mol
Mass of fluorine:
Mass = number of moles × molar mass
Mass = 1.32 mol ×19 g/mol
Mass = 25.08 g
Answer:
0.015 M HNO3 = 0.015 M H3O+ pH = -log(0.015) = 1.82 [OH -] = 1.0 x 10 -14/0.015 M = 6.7 x 10 13 Check: HNO3 is a strong acid, so we expect the pH to be low and the [OH ] to be small
