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2 years ago

What is the value of X ?

Mathematics

1 answer:

hjlf2 years ago

8 0

Because both lines DE and XY are parallel to one another, the 115° will be same for the line segment. XY

And because XY is a flat line, it's a straight angle. Meaning it's an 180° angle.

We need to find a value of x that when added 115° will equal 180°.

We can use this equation: x + 115 = 180

Subtract both sides 115.

x + 115 - 115 = 180 - 115
x = 65

So, x is equal to 65 degrees.

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Members of the student concil are conducting a fundraiser by selling school calendars. After selling 80 calendars, they had a lo

Oksana_A [137]

Answer:

a) $y=8x-1000$

b) $profit=\$8$

c) They'd have lost $1000 if they had sold no calendars.

Step-by-step explanation:

a) The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

In this case we know that "y" represents the profit of loss and "x" the number of calendars sold.

Then, according to the exercise, the line passes through these two points:

$(80,-360)$ and $(200,600)$

Then, we can find the slope of the line with the formula $m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-360-600}{80-200}=8$

Now, we can substitute the slope and one of those points into $y=mx+b$ and solve for "b":

$600=8(200)+b\\\\b=-1000$

Then, subtituting values, we get that the equation that describes the relation between the profit of loss and the number of calendars sold, is:

$y=8x-1000$

b) The slope of the line is the profit they made from selling each calendar

$profit=8$

c) The y-intercept is the amount they would have lost if they had sold no calendars:

$b=-1000$

They'd have lost $1000 if they had sold no calendars.

6 0

2 years ago

A student claims that 8^3 x 8^-5 is greater than 1. Explain whether the student is correct or not.

nlexa [21]

Remember:
a^m * a^n=a^(m+n)
a^-m=1/a^m

8³ x 8⁻⁵=8³⁻⁵=8⁻²=1/8²=1/64<1

Answer: the student is not correct, because 1/64<1, and 8³ x 8⁻⁵=1/64.

7 0

3 years ago

Mr Abraham is able to divide the learners in his mathematics class into equal groups of 2, 5 or 6 without leaving any learners o

IRISSAK [1]

Answer:

Step-by-step explanation:

Find the lowest number divisible by both 6, 5, and 2.

To start, let's list off the numbers divisible by six, and see if we can check any of them off for 5. Since both 2 and 6 are even numbers, we know that if a number is divisible by 6, it's divisible by 2.

6 12 18 24 30 36 42 48 54 60

All of these numbers are divisible by two. Let's find the lowest one that is divisible by 5. We know this by either the umber ending in 5 or 0.

30 is the lowest number that is divisible by 2, 5, or 6.

3 0

2 years ago

340 pages; 20% decrease=? (With work plz)

pishuonlain [190]

340 × .2 = 68

68 page decrease

340 - 68 = 272

272 pages left

4 0

3 years ago

What are the vertex and x-intercepts of the graph of the function given below?

olchik [2.2K]

The correct question is
What are the vertex and x-intercepts of the graph of the function given below?
y = x²-2x-35

step 1
convert the equation in the vertex form
y+35=x²-2x
y+35=(x²-2x+1-1)
y+35+1=(x²-2x+1)
y+36=(x-1)²------> equation in the vertex form

the vertex is the point (1,-36)

the answer Part a) is
the vertex is the point (1,-36)

Part b) Find the x-intercepts
we know that
the x-intercepts is when y=0
so
y+36=(x-1)²
for y=0
(x-1)²=36
(+/-)(x-1)=√36-------> (+/-)(x-1)=6
(+)(x-1)=6------> x=6+1-----> x=7
(-)(x-1)=6-----> x=1-6-----> x=-5

the x-intercepts are the points
(7,0) and (-5,0)

the answer part b) is
the x-intercepts are the points (7,0) and (-5,0)

the total answer is the option
A. Vertex: (1, -36); x-intercepts: (7, 0) and (-5, 0)

6 0

3 years ago