Answer:
see below
Step-by-step explanation:
![-2(4 - \frac{x}{2} )^{5} + C](https://tex.z-dn.net/?f=-2%284%20-%20%5Cfrac%7Bx%7D%7B2%7D%20%29%5E%7B5%7D%20%2B%20C)
Think of the above as:
* ![(\frac{8}{2} - \frac{x}{2} )^{5} + C](https://tex.z-dn.net/?f=%28%5Cfrac%7B8%7D%7B2%7D%20-%20%5Cfrac%7Bx%7D%7B2%7D%20%29%5E%7B5%7D%20%2B%20C)
=
* ![\frac{(8 - x)^{5}}{2^{5}} + C](https://tex.z-dn.net/?f=%5Cfrac%7B%288%20-%20x%29%5E%7B5%7D%7D%7B2%5E%7B5%7D%7D%20%20%2B%20C)
=
* ![\frac{(8 - x)^{5}}{32} + C](https://tex.z-dn.net/?f=%5Cfrac%7B%288%20-%20x%29%5E%7B5%7D%7D%7B32%7D%20%20%2B%20C)
=
* ![\frac{(8 - x)^{5}}{16} + C](https://tex.z-dn.net/?f=%5Cfrac%7B%288%20-%20x%29%5E%7B5%7D%7D%7B16%7D%20%20%2B%20C)
= ![\frac{-1(8 - x)^{5}}{16} + C](https://tex.z-dn.net/?f=%5Cfrac%7B-1%288%20-%20x%29%5E%7B5%7D%7D%7B16%7D%20%20%2B%20C)
= ![\frac{(-8 + x)^{5}}{16} + C](https://tex.z-dn.net/?f=%5Cfrac%7B%28-8%20%2B%20x%29%5E%7B5%7D%7D%7B16%7D%20%20%2B%20C)
Can flip it around to be...
![\frac{(x - 8)^{5}}{16} + C](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%20-%208%29%5E%7B5%7D%7D%7B16%7D%20%20%2B%20C)
Your answers should be B and D
When naming angles, they all need to be connected on the line without overlapping any points previously said. Angle YXZ is incorrect because X is not on the same line as Z. YW is a line because both sides continue on forever, as indicated by the arrows.
Hope this helps!
Answer:
2,995 or 35,940(?)
Step-by-step explanation:
I don't exactly remember how to do this so, I'll show you two different ways I solved this
Use the formula I=P*r*t
I=Interest
P=Principal
r=rate
t=time
To solve this you'll have to...
The principal is 29,950, the rate is 5% but it'll become a decimal which is 0.05, and the time is 2
Put it into the formula form 29,950*0.05*2= 2,995 in interest
Or...
You'll use the same formula, but this time multiply 0.05 by 12 since there are 12 months in one year which is 0.6, so...
29,950*0.6*2=35,940 in interest
I hope one works!
Answer:
m∠C = 122°
Step-by-step explanation:
Opposite angles of a quadrilateral inscribed in a circle are supplementary. This means
m∠A + m∠C = 180°
m∠B + m∠D = 180°
To find angle C we need to find x, then subtract m∠A from 180°
x+20=3x
20=2x
x=10
Now we substitute 10 in for x
m∠A=2(10)+38
m∠A=20+38
m∠A=58°
Now we subtract this value from 180.
m∠C=180-58
m∠C=122°