Question

Simplify: title="\sqrt[3]{\frac{x^2}{8y^{-1}} }" alt="\sqrt[3]{\frac{x^2}{8y^{-1}} }" align="absmiddle" class="latex-formula">

Thank you!

Answer 1

Answer:

hope this will help you more

good luck...

Answer 2

Answer:

$\frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2}$

Answer C is correct

Step-by-step explanation:

$\sqrt[3]{ \frac{ {x}^{2} }{8 {y}^{ - 1} } } \\ \frac{ {x}^{2 \times \frac{1}{3} } \times {y}^{1 \times \frac{1}{3} } }{ \sqrt[3]{8} } \\ = \frac{ {x}^{ \frac{2}{3} } {y}^{ \frac{1}{3} } }{2}$