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3 years ago

What 2 sides need to be congruent in order to prove the 2 triangles are congruent by HL?

Mathematics

2 answers:

IgorLugansk [536]3 years ago

8 0

Answer:

AB=ED

Step-by-step explanation:

Sphinxa [80]3 years ago

3 0

Answer:

The two hypotenuses.

Step-by-step explanation:

HL or Hypotenuse-Leg Theorem: two right triangles are congruent if and only if the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of the other right triangle.

Since we already know the bottom leg of each triangle is congruent, we only need to know the two hypotenuses.

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Find the mode for the scores 3,760, 5,200, 8,750, 4,400, 5,250

V125BC [204]

Answer:

no mode

Step-by-step explanation:

no number appears more than once

therefore there is no mode

3 0

2 years ago

Solve for q<br> (Please show all work thank you:))

Masja [62]

Answer:

q = ± $\frac{5}{4\sqrt{p} }$

Step-by-step explanation:

We are to solve for q in:

16pq² = 25

q² = $\frac{25}{16p}$

$\sqrt{q^2}$ = ± $\sqrt{\frac{25}{16p} }$ = ± $\frac{5}{4\sqrt{p} }$

5 0

3 years ago

Your Neighbor has a square-shaped pool with side lengths of 3a^5. What is the area of the pool?

lbvjy [14]

Square Area: $A=s^2$ , with s = length of side

Plug in the side length into the square area and solve for the area as such:

$A=(3a^5)^2\\A=9a^{10}$

<u>The area of the pool is 9a^10 un^2.</u>

7 0

4 years ago

Read 2 more answers

How do you subtract rational expressions without a common denominator?

zubka84 [21]

You would have to make common denominators
consider a/b,c/d in Q
then a/b - c/d = ad/db - cb/bd = (ad-cb)/db for all a,b,c,d in R, exclude b,d=0
i.e. 1/2 - 1/4
=4/8 - 2/8 =(4-2)/8=2/8 =1/4

4 0

3 years ago

ANSWER NUMBER 7 FOR 20 POINTS

pashok25 [27]

#7

d/2 +d/5 + d/3 = 3
(15d + 6d + 10d) / 30 = 3
15d + 6d + 10d = 90
31d = 90
d = 90/31
d = 2 28/31

6 0

3 years ago