We are given two relations
(a)
Relation (R)
![R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]](https://tex.z-dn.net/?f=R%3D%5B%28%28k-8.3%2B2.4k%29%2C-5%29%2C%28-%5Cfrac%7B3%7D%7B4%7Dk%2C4%29%5D)
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k







............Answer
(b)
S = {(2−|k+1| , 4), (−6, 7)}
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k




Since, this is absolute function
so, we can break it into two parts


we get




so,
...............Answer
Answer:
x = 12
Step-by-step explanation:
Angle GHK is half of 120, so is 60. Then ...
3x +24 = 60
3x = 36 . . . . . subtract 24
x = 12 . . . . . . . divide by 3
Answer:
(-1, -1)
Step-by-step explanation:
Let's set these two equations equal to each other to solve the system:
x = 2x + 1
Solving for x, we get x = -1
Plug this value of x back into any of the two equations to get y: y = 2 * (-1) + 1 = -1.
Thus, the point of intersection is (-1, -1).
Hope this helps!
Answer:
0, -2, 2, -1
Step-by-step explanation:
You are trying to make it so that the one of the ( )= 0.
An example is (x+15) or (2x+3)
the first l one would be x= -15 since -15+15 would equal 0.
The second one is -3/2 since it would be -3+3 which would equal 0.
also since the equation starts with x( or -x it doesn't really matter) one of the zeros would also be 0.
Hope this helps!
Yes!! They both are equivalent.....