3 years ago

PLEASE HELP ASAP!! BRAINLIEST!!

Mathematics

2 answers:

sdas [7]3 years ago

5 0

Answer:

third option

Step-by-step explanation:

Using the rule of exponents/ radicals

$a^{\frac{m}{n} }$ = $\sqrt[n]{a^{m} }$ , then

$2^{\frac{4}{3} }$

= $\sqrt[3]{2^{4} }$

= $\sqrt[3]{16}$

Elan Coil [88]3 years ago

3 0

Answer:

Option 3

Step-by-step explanation:

${2}^{ \frac{4}{3} } = \sqrt[3]{ {2}^{4} } = \sqrt[3]{16}$

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X² + y² = 8

ohaa [14]

Answer:

$(2,2)~ \text{and}~ (-2,-2)$

Step by step explanation:

$x^2 +y^2 =8~~~~~~...(i)\\\\x-y=0~~~~~~~~~...(ii)\\\\\text{From (ii):}\\\\x-y = 0 \implies x = y\\\\\text{Substitute x = y in eq (i):}\\\\~~~~~~y^2 +y^2 =8\\\\\implies 2y^2 = 8\\ \\\implies y^2 = \dfrac 82\\\\\implies y^2 = 4\\\\\implies y = \pm\sqrt 4\\\\\implies y = \pm 2\\\\\text{Substitute y = x in equation (i):}\\ \\~~~~~~x^2 +x^2 = 8\\ \\\implies 2x^2 = 8\\\\\implies x^2 = \dfrac 82\\\\\implies x^2 = 4\\\\\implies x = \pm\sqrt 4\\\\\implies x = \pm2\\\\$