Hey there!!
In order to solve this equation, we will have to use the distributive property.
What is distributive property?
We will need to distribute one term to the other terms preset.
Example : 4 ( 3x - 1 )
sing distributive property, we will have to distribute the term outside the parenthesis to the terms inside. In this case, we will have to distribute 4 to 3x and -1
( 4 × 3x ) + ( 4 × -1 )
12x + ( -4 )
= 12x - 4
This is after implementing the distributive property.
Now moving back onto the question
4 ( x + 5 ) = 3 ( x - 2 ) - 2 ( x + 2 )
Let us first solve 4 ( x + 5 )
Distribute 4 to x and 5
( 4 × x ) + ( 4 × 5 )
4x + 20
Now let's solve 3 ( x - 2 )
Distribute 3 to x and -2
( 3 × x ) + ( 3 × - 2 )
3x - 6
Solve for -2 ( x + 2 )
Distribute -2 to x and 2
( -2 × x ) + ( -2 × 2 )
-2x - 4
Now, let's get everything back together
4x + 20 = 3x - 6 - 2x - 4
Combine all the like terms
4x + 20 = x - 10
Adding 10 on both sides
4x + 20 + 10 = x - 10 + 10
4x + 30 = x
Subtracting 4x on both sides
4x - 4x + 30 = x - 4x
30 = -3x
Dividing by -3 on both sides
30 / -3 = -3x / -3
- 10 = x
<h2>x = - 10 </h2><h3>Hope my answer helps!</h3>
Answer:
1. C. cylindrical coordinates
2 A. spherical coordinates
3. A. spherical coordinates
4. D. Cartesian coordinates
5 B. polar coordinates
Step-by-step explanation:
USE THE BOUNDARY INTERVALS TO IDENTIFY
1. ∭E dV where E is:
x^2 + y^2 + z^2<= 4, x>= 0, y>= 0, z>= 0 -- This is A CYLINDRICAL COORDINATES SINCE x>= 0, y>= 0, z>= 0
2. ∭E z^2 dV where E is:
-2 <= z <= 2,1 <= x^ 2 + y^2 <= 2 This is A SPHERICAL COORDINATES
3. ∭E z dV where E is:
1 <= x <= 2, 3<= y <= 4,5 <= z <= 6 -- This is A SPHERICAL COORDINATES
4. ∫10∫y^20 1/x dx ---- This is A CARTESIAN COORDINATES
5. ∬D 1/x^2 + y^2 dA where D is: x^2 + y^2 <=4 This is A POLAR COORDINATES
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Step-by-step explanation:
Hi there!
The given equation is:
y = -2x + 5………………(i)
Comparing the equation with y = mx+c, we get;
m1 = -2
Also another equation of the line which passes through point (-4,2), we get;
(y-2) = m2(X+4)............(ii) { using the formula (y-y1) = m2(x-x2)}
According to the question, they are perpendicular to eachother, So according to the condition of perpendicular lines;
m1*m2 = -1
-2*m2 = -1
or, m2 = 1/2.
Therefore, m2= 1/2.
Now, keeping the value of m2 in equation (ii).
(y-2) = 1/2(x+4)
y = (1/2)x + 4
Therefore, the required equation is: y = (1/2)x + 4.
<u>Hope</u><u> it</u><u> helps</u><u>!</u>
Answer:
A and C on Edge
Step-by-step explanation:
Just completed the assignment