Determine the value(s) of x at which the function f(x)=x⁴-8x² +2 has a horizontal tangent.

1 answer:

3 0

Answer:

$4 {x}^{3} - 16x = 0 \\ 4x( {x}^{2} - 4) = 0 \\ 4x(x - 2)(x + 2) = 0 \\ x = 0or \: or - 2$

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Determine the value(s) of x at which the function f(x)=x⁴-8x² +2 has a horizontal tangent. ​