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2 years ago

Determine the value(s) of x at which the function f(x)=x⁴-8x² +2 has a horizontal tangent.

Mathematics

1 answer:

Slav-nsk [51]2 years ago

3 0

Answer:

$4 {x}^{3} - 16x = 0 \\ 4x( {x}^{2} - 4) = 0 \\ 4x(x - 2)(x + 2) = 0 \\ x = 0or \: or - 2$

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schepotkina [342]

Answer:

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Step-by-step explanation:

Monthly interest payment rate :

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3 years ago

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Maurinko [17]

Answer:

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Step-by-step explanation:

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2 years ago

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Ne4ueva [31]

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svp [43]

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Determine the value(s) of x at which the function f(x)=x⁴-8x² +2 has a horizontal tangent. ​

Determine the value(s) of x at which the function f(x)=x⁴-8x² +2 has a horizontal tangent.