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alexandr402 [8]
3 years ago
15

Determine the value(s) of x at which the function f(x)=x⁴-8x² +2 has a horizontal tangent. ​

Mathematics
1 answer:
Slav-nsk [51]3 years ago
3 0

Answer:

4 {x}^{3}  - 16x = 0 \\ 4x( {x}^{2}  - 4) = 0 \\ 4x(x - 2)(x + 2) = 0 \\ x = 0or \: or - 2

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Step-by-step explanation:

\tt{2(x+1.25)=3.5  } ⠀

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