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amid [387]
3 years ago
10

What do you wish you had learned is Digital Citizenship class?

Physics
1 answer:
nydimaria [60]3 years ago
7 0

Answer:

I wish I learned what I could do in the real world with the information I learned

Explanation:

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8 0
3 years ago
Radiation from the sun hits Earth unequally and is absorbed by different materials in varying amounts. This is called
GenaCL600 [577]

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sorry I don't know what is the answer of this question

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4 0
2 years ago
Pls what is the formula for specific heat capacity in physics and pls follow ​
lina2011 [118]

Answer:

<h3>The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.</h3>
5 0
3 years ago
Two object, one of mass m and the other of mass 2m, are dropped from the top of a building. if there is no air resistance, when
ra1l [238]

Answer:

They hit the ground at the same time

Explanation:

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3 0
3 years ago
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o
Schach [20]

Explanation:

The given data is as follows.

       Temperature of metal = 296^{o}C = (296 + 273) K

                                            = 569 K

     Density of the metal = 8.85 g/cm^{3} = 8.85 \times 10^{-6} g/m^{3}      (as 1 cm^{3} = 10^{-6} m^{3})

     Atomic mass = 51.40 g/mol

    Vacancies = 9.19 \times 10^{23} m^{-3}

Formula to calculate the number of atomic sites is as follows.

           n = \frac{\rho \times N_{A}}{\text{atomic weight}}

              = \frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}

              = 1.036 \times 10^{17} atom/m^{3}

Now, we will calculate the energy as follows.

                E = -KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})

where,    K = 8.62 \times 10^{-5}

         E = -8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})

               = 78.46 eV/atom

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is 78.46 eV/atom.

6 0
4 years ago
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