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Evgesh-ka [11]
3 years ago
5

Which characteristics describe the troposphere? Select two options.

Physics
2 answers:
lesantik [10]3 years ago
5 0

Answer:

is the innermost layer,

has the highest air pressure

Explanation:

The troposphere is the lowest layer of Earth's atmosphere and site of all weather on Earth. The troposphere is bonded on the top by a layer of air called the tropopause, which separates the troposphere from the stratosphere, and on bottom by the surface of the Earth.

gtnhenbr [62]3 years ago
5 0

Answer:

is the innermost layer

has the highest air pressure

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A 0.15 kg ball is moving with a velocity of<br> 35 m/s. Find the momentum of the ball.
GarryVolchara [31]

Answer:

<h2>5.25 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.15 × 35

We have the final answer as

<h3>5.25 kg.m/s</h3>

Hope this helps you

4 0
3 years ago
Which kind of energy transformation occurs during skydiving? A) mechanical to gravitational B) gravitational to kinetic C) kinet
Aleks [24]

B) gravitational to kinetic

Explanation:

The skydiver, when he is located at a certain height h above the ground, possesses gravitational potential energy, equal to:

U=mgh

where m is the mass of the skydiver, g is the gravitational acceleration and h is the height above the ground. As he falls, its height h decreases, while his speed v increases, so part of the gravitational potential energy is converted into kinetic energy, which is given by

K=\frac{1}{2}mv^2

so, we see that as v increases, the kinetic energy increases. Therefore the correct answer is

B) gravitational to kinetic

7 0
3 years ago
Read 2 more answers
The magnitude J(r) of the current density in a certain cylindrical wire is given as a function of radial distance from the cente
Gennadij [26K]

Answer:

18.1 × 10⁻⁶ A = 18.1 μA

Explanation:

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Since J(r) = Br, in the cylindrical wire. With width of 10.0 μm, dr = 10.0 μm. r = 1.20 mm. We have a differential current dI. We integrate first by integrating dθ from θ = 0 to θ = 2π.

So, dI = J(r)rdrdθ

dI/dr = ∫J(r)rdθ = ∫Br²dθ = Br²∫dθ = 2πBr²

Now I = (dI/dr)dr at r = 1.20 mm = 1.20 × 10⁻³ m and dr = 10.0 μm = 0.010 mm = 0.010 × 10⁻³ m

I = (2πBr²)dr = 2π × 2.00 × 10⁵ A/m³ × (1.20 × 10⁻³ m)² × 0.010 × 10⁻³ m  =  0.181 × 10⁻⁴ A = 18.1 × 10⁻⁶ A = 18.1 μA

3 0
3 years ago
in a circuit, where do electric charges go once they have left the voltage source and traveled along the wires?
S_A_V [24]
In an electric circuit, the free electrons are moving around. Since equal charges repel and opposite charges attract, the electrons move from the negatively charged to the positively charged pole of the voltage source.
7 0
3 years ago
A surface receiving sound is moved from its original position to a position three times farther away from the source of the soun
777dan777 [17]
Intensity, E follows inverse square law.

E α  1/r²

r is the distance.

So if the distance r is increased by 3, the intensity would be reduced by 3²

3² = 9

So the answer is nines times as low.  C. 
3 0
3 years ago
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