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harina [27]
3 years ago
12

How to play track and field

Physics
2 answers:
Ahat [919]3 years ago
3 0

Explanation:

Track and Field is a sport, which is includes disciplines of running, jumping, and throwing events. The sport traces back to Ancient Greece. The first recorded examples of this sport were at the Ancient Greek Olympics. In Ancient Greece, only one event was contested, the stadion footrace. Later on, the game expanded to more events.Events of track and field are divided into three: track events, field events, and combined events. Track events consist of Sprints, middle-distance, long distance, hurdles and relays; Field events consist of jumps and throws; while combined events consist of pentathlon, heptathlon, and decathlon. Track and field is usually played outdoors in stadiums. The usual features of a track and field stadium are the outer running track, and the field within the track

KATRIN_1 [288]3 years ago
3 0
When Konami ported their arcade hit Track & Field to the Famicom (as Hyper Olympic), they only included four out of six events. Afterwards, they converted Hyper Sports to the Famicom as well, this time including three of the Hyper Sports events and one more event from Track & Field. By the time the NES gained popularity in the United States, Konami retooled the game for release in America by including all eight events from both games in one cartridge. Of the original six events from Track & Field, only the hammer throw is missing; in its place, however, are skeet shooting, archery, and triple jump.
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Peter designed a road with a curve of radius 30 m that is banked so that a 950 kg car traveling at 40.0 km/h can round it even i
spayn [35]

Answer:

v = 15.56 m/s

v = 56 km/h

Explanation:

When coefficient of friction is approximately zero then we have

F_ncos\theta = mg

F_n sin\theta = \frac{mv^2}{R}

tan\theta = \frac{v^2}{Rg}

here we know that

v = 40 km/h = 11.11 m/s

R = 30 m

tan\theta = \frac{11.11^2}{30\times 9.81}

\theta = 22.75 degree

now when friction coefficient is 0.30 then we have

F_n cos\theta = mg + F_f sin\theta

F_f cos\theta + F_n sin\theta = \frac{mv^2}{R}

now we have

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