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chubhunter [2.5K]
2 years ago
9

Jack has $24 in one-dollar and five- dollar bills. He has a total of 8 bills. How many of each bill does he have?​

Mathematics
2 answers:
Marysya12 [62]2 years ago
8 0

Answer:

4 fives and 4 ones

Step-by-step explanation:

mylen [45]2 years ago
3 0
He has 4 $5 bills and 4 $1 bills
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Determine the measure of angle j: angle k: & angle: l
Vikki [24]

Answer:

17=J

L= 180-17

 = 163

K=163

L=163

J=17

Step-by-step explanation:

3 0
2 years ago
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
Help fast plss i have 0 brain cells to do this
Maslowich
The answer is the third one
6 0
2 years ago
Read 2 more answers
Help! WHAT IS THE VALUE OF X, and can you show how you got it please?
miss Akunina [59]
See the picture attached with letters to better understand the problem

in the right triangle ABD
applying the Pythagoras theorem
8²=AD²+(x+4)²-----> AD²=64-(x+4)²------> equation 1

in the right triangle ADC
applying the Pythagoras theorem
12²=AD²+(2x+1)²-----> AD²=144-(2x+1)²------> equation 2

equate equation 1 and equation 2
64-(x+4)²=144-(2x+1)²-------> 64-[x²+8x+16]=144-[4x²+4x+1]
64-x²-8x-16=144-4x²-4x-1
4x²-x²-8x+4x=144-1-64+16
3x²-4x=95
3x²-4x-95=0

using a graph tool----> to resolve the second order equation
see the attached figure N 2
the solution is
x=6.33

the answer is
x=6.33 units

3 0
3 years ago
Help plzz ill gve brailiest
kogti [31]

Answer:

The 2nd answer is the correct

Step-by-step explanation:

Hope this helps:)

3 0
3 years ago
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