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3 years ago

. Explain the differences between a sponge and a sourdough starter. How are each of these items used

Chemistry

1 answer:

d1i1m1o1n [39]3 years ago

8 0

Answer:

Less time is required when using the sponge method than with the sourdough method, and although the sponge method provides hints of the depth of flavor and texture that result from the sourdough method, these characteristics are not as pronounced as they are when using the sourdough method.

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Ype the correct answer in the box.

OLga [1]

Explanation:

here is your answer. Hope it helps

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3 years ago

15. Frog lungs are poorly developed. How does this relate to their skin being thin and moist?

Nataly [62]

The answer is that they havent reached their full form yet.

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3 years ago

Read 2 more answers

A student dissolves 15.g of sucrose C12H22O11 in 300.mL of a solvent with a density of 1.13/gmL. The student notices that the vo

Kruka [31]

Answer: The molarity and molality of sucrose solution is 0.146 M and 0.129 m respectively

Explanation:

Calculating the molarity of solution:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of sucrose = 15 g

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 300 L

Putting values in above equation, we get:

$\text{Molarity of sucrose solution}=\frac{15\times 1000}{342.3\times 300}\\\\\text{Molarity of sucrose solution}=0.146M$

Hence, the molarity of sucrose solution is 0.146 M

Calculating the molality of solution:

To calculate the mass of solvent, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solvent = 1.13 g/mL

Volume of solvent = 300 mL

Putting values in above equation, we get:

$1.13g/mL=\frac{\text{Mass of solvent}}{300mL}\\\\\text{Mass of solvent}=(1.13g/mL\times 300mL)=339g$

To calculate the molality of solution, we use the equation:

$\text{Molality of solution}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

$m_{solute}$ = Given mass of solute (sucrose) = 15 g

$M_{solute}$ = Molar mass of solute (sucrose) = 342.3 g/mol

$W_{solvent}$ = Mass of solvent = 339 g

Putting values in above equation, we get:

$\text{Molality of solution}=\frac{15\times 1000}{342.3\times 339}\\\\\text{Molality of solution}=0.129m$

Hence, the molality of sucrose solution is 0.129 m

5 0

4 years ago

The mass of a quantity of Cl gas (70,906 g/mol) that occupies 50.0L at 27.0°C and 721 mm Hg is:

inessss [21]

We need no of moles

Apply ideal gas equation

PV=nRT
n=PV/RT
n=721(50)/8.314(300)
n=14.4mol

mass

70.906(14.4)
1021g

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2 years ago

A(n)_______is a balanced chemical equation that includes the

Katyanochek1 [597]

Answer:

thermochemical equation

Explanation:

A(n)__thermochemical equation_____is a balanced chemical equation that includes the physical states of all reactants and products, and the energy change that accompanies the reaction.

7 0

3 years ago