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2 years ago

The mass of a quantity of Cl gas (70,906 g/mol) that occupies 50.0L at 27.0°C and 721 mm Hg is:

Chemistry

1 answer:

inessss [21]2 years ago

4 0

We need no of moles

Apply ideal gas equation

PV=nRT
n=PV/RT
n=721(50)/8.314(300)
n=14.4mol

mass

70.906(14.4)
1021g

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What three compounds are produced by the combustion of hydrocarbon fuels?

MakcuM [25]

The most common hydrogen carbon fuels are ethanol and diesel and their product of combustion is carbon dioxide, water and heat .

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3 years ago

What could be the fourth quantum number of a 1s^2 electron be?

Bumek [7]

The forth quantum number is Spin quantum number and the value of Spin Quantum Number of 1s² will be +1/2. Therefore, the correct option is (B) option

<h3>What is Spin Quantum Number ?</h3>

It describes the orientation of the electron spin (rotation) in space.

In the given case of 1s² configuration,

since, the Quantum numbers are known as:

Principal quantum number (n) which cannot be zero.

The allowed values of n are therefore 1, 2, 3, 4, and so on.

Angular quantum number (l) is able to be any integer between 0

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If n = 2, l can be either 0 or 1.

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Therefore, for example, If l = 3, m can be either -3 to +3.

Spin Quantum Number (ms): Ms = +½ or -½ accounts for the orientation of the spin axis of an electron as it is able to spin in only one of two directions.

Thus, since the fourth quantum number is Ms, spin, we infer that the answer is (B) option ie, Ms = +1/2 because it represents the positive spin on 1s².

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6 0

2 years ago

How much heat is needed to change the temperature of 5g of water from 20 oC to 37 oC?

Dafna1 [17]

Answer:

The answer to your question is Q = 355.64 J

Explanation:

Data

Heat = Q = ?

Temperature 1 = T1 = 20°C

Temperature 2 = T2 = 37°C

mass = m = 5 g

Specific heat = Cp = 4.184 J/g°C

Formula

Q = mCp(T2 - T1)

-Substitution

Q = (5)(4.184)(37 - 20)

-Simplification

Q = (5)(4.184)(17)

-Result

Q = 355.64 J

5 0

3 years ago

Read 2 more answers

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Reil [10]

The balanced chemical equation for the production of chromium metal from the reaction of chromium(ll) nitrate reacts with a strip of zinc is:

3 Zn + 2 Cr(NO₃)₃ → 2 Cr + 3 Zn(NO₃)₂

This is a redox reaction, which <u>is a chemical reaction in which one or more electrons are transferred between the reagents</u>, causing a change in their oxidation states. In the proposed reaction, Cr oxidation state goes from +3 to 0, becoming metallic chromium, while Zn goes from being Zn⁰ to Zn²⁺.

<u>The mass of chromium metal produced in the above reaction will be,</u>

425.0 mL x $\frac{1 L}{1000 mL}$ x $\frac{0.25 mol Cr(NO_{3})_{3} }{1 L}$ x $\frac{2 mol Cr }{2 mol Cr(NO_{3})_{3} }$ x $\frac{51.9961 g Cr}{1 mol Cr}$ = 5.52 g

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Answer:

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3 years ago