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SOVA2 [1]
3 years ago
12

How to make a explosion at home with normal stuff​

Chemistry
1 answer:
navik [9.2K]3 years ago
5 0

answer:

cleaning products

Explanation:

causes chemical reactions when mixed

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The following image is of a diatom. It lives in water and gets food from photosynthesis. It is encased in a hard shell made of s
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the correct answer is A

A diatom is a(n) <u>Singled-celled organism</u> because it has <u>only one cell.</u>

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7 0
3 years ago
Valence electrons determine an atom’s __________. a. mass c. atomic number b. chemical properties d. period
poizon [28]
Hey there !

Answer B

Chemical properties are characteristic behaviors of a substance when it is found in the presence of another substance. To investigate chemical properties we will have to carry out chemical transformations (performing chemical tests) and it is generally not possible to recover the sample used (because it suffers changes giving rise to other substances).

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6 0
4 years ago
Compared to the physical and chemical properties of the compound NO2, the compound N2O has
Lelu [443]

Answer:

B

Explanation:

The two compounds have different physical properties and different chemical properties despite the fact that they are formed from nitrogen and oxygen.

8 0
4 years ago
Based on their positions in the periodic table, which of the following elements would you expect to have the highest electronega
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8 0
3 years ago
A platinum ball with a mass of 100 g is removed from a furnace and dropped into 400 g of water at 0 ◦C. If the equilibrium tempe
NemiM [27]

Answer:

1,298 °C was the temperature of the furnace.

Explanation:

Heat lost by platinum will be equal to heat gained by the water

-Q_1=Q_2

Mass of platinum = m_1=100 g

Specific heat capacity of platinum= c_1=130 J/kg^oC =0.130 J/g^oC

Initial temperature of the iron = T_1=?

Final temperature = T_2=T  = 10°C

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2= 400 g

Specific heat capacity of water= c_2=4.186 J/g^oC

Initial temperature of the water = T_3=0^oC

Final temperature of water = T_2=T  = 10°C

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(100 g\times 0.130 J/g^oC\times (10^oC-T_1))=400\times 4.186\times (10^oC-0^oC)

we get, T_1 = 1,298°C

1,298 °C was the temperature of the furnace.

6 0
4 years ago
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