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2 years ago

What is the probability of pulling a blue marble AND THEN a red marble from a bag of 6 blue, 2 red, and 4 purple marbles?

Mathematics

2 answers:

Tom [10]2 years ago

5 0

The answer will be: one out of twelve.

LenKa [72]2 years ago

4 0

Answer:

Step-by-step explanation:

this is probability wrong ... hahaha

You might be interested in

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

3 years ago

Which of the sets of ordered pairs represents a function?

alexandr1967 [171]

Answer:

The correct option is 4. Neither A nor B represents a function.

Step-by-step explanation:

The given sets of ordered pairs are

$A=\{(1,-5), (8,-5), (8,7), (2,9)\}$

$B=\{(7,-4), (7,-2), (6,-3), (-9,5)\}$

A set of ordered pairs represents a function if there exist unique outputs for all inputs. It means for each values of x there exist, a unique value of y.

In set A the value of y-coordinates are -5 and 7 at $x=8$ .

At x=8, there exist more than one value of y, so the set A is not a function.

In set B the value of y-coordinates are -4 and -2 at $x=7$ .

At x=7, there exist more than one value of y, so the set B is not a function.

Therefore neither A nor B represents a function and option 4 is correct.

3 0

3 years ago

Read 2 more answers

A roller coaster begins at ground level, rises 63 feet, then falls 71 feet. What is the

meriva

Answer:

-8 feet

Step-by-step explanation:

63 - 71 = -8

3 0

3 years ago

The sum of three consecutive integers is 126..............

Rasek [7]

The three consecutive integers are: x, (x+1) and (x+2).
We can suggest this equation:
x+(x+1)+(x+2)=126
3x+3=126
3x=126-3
3x=123
x=123/3
x=41

x=41
(x+1)=41+1=42
(x+2)=41+2=43

Answer: the three consecutive integers would be: 41,42 and 43.

6 0

3 years ago

The army bus has 12 seats on one side. Two soldiers can sit in each seat. If five seats are reserved for equipment, how many bus

marissa [1.9K]

Answer:

80 buses will be required for 1120 soldiers.

Step-by-step explanation:

Given:

Number of seats on One side = 12 seats.

Now Given:

five seats are reserved for equipment.

So we can say that;

Number of seats used by soldiers = $12-5=7\ seats$

Number of soldiers on Each seat =2

So we will now find number of soldiers on each bus.

number of soldiers on each bus is equal to Number of seats used by soldiers multiplied by Number of soldiers on Each seat.

framing in equation form we get;

number of soldiers on each bus = $7\times2 = 14\ soldiers$

Now we know that;

For 14 soldiers = 1 bus

So 1120 soldiers = Number of buses required for 1120 soldiers.

By Using Unitary method we get;

Number of buses required for 1120 soldiers = $\frac{1120}{14} =80$

Hence 80 buses will be required for 1120 soldiers.

3 0

3 years ago