All categories

3 years ago

Need help with this question

Mathematics

1 answer:

-Dominant- [34]3 years ago

7 0

Answer:

Step-by-step explanation:

In a right triangle, the side opposite the right angle is the largest side as the right angle represents the largest angle in the triangle. Therefore, as 17.5 is opposite the right angle, we can say that AB²+10²=17.5², and √(17.5²-10²)=AB = 14.4

Using sohcahtoa, we can establish that

sin(∠C) = opposite/hypotenuse = 14.4/17.5, and

arcsin(14.4/17.5) = ∠C = 55°

Because the angles in a right triangle add up to 180 degrees, we can say that ∠A+∠B+∠C = 180°, so ∠A + 90 + 55 = 180 and ∠A = 35°

You might be interested in

Geometry!!! Pls help!! Mathxl!! Full points!!

ololo11 [35]

Answer:

3 both sides

Step-by-step explanation:

3 0

2 years ago

Terrell loves to listen to music, so he buys a subscription to a music-streaming service. He pays $4.99 each month. How much doe

Ilya [14]

Answer:

$Yearly = \$59.88$

Step-by-step explanation:

Given

$Monthly = \$4.99$

Required

Determine the yearly cost

To do this, we multiply the monthly subscription by 12

$Yearly = Monthly * 12$

$Yearly = \$4.99 * 12$

$Yearly = \$59.88$

<em>Hence, the yearly servics cost is $59.88</em>

4 0

3 years ago

The perimeter of a rectangular baking sheet is 58 inches and its area is 201.25 in.2. What are the length and width of the bakin

anzhelika [568]

Answer:

$Length=17.5\ in\\\\Width=11.5\ in$

Step-by-step explanation:

The formula for calculate the Area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width.

And the formula for calculate the peimeter of a rectangle is:

$P=2l+2w$

Where "l" is the lenght and "w" is the width.

We know that the perimeter of the rectangular baking sheet is 58 inches and its area is 201.25 in². Then:

$A=201.25\ in^2\\\\P=58\ in$

<u>The steps are:</u>

1. Solve for the "l" from the formula $A=lw$ :

$A=lw\\\\l=\frac{A}{w}\\\\\l=\frac{201.25}{w}$

2. Substitute $l=\frac{201.25}{w}$ into the formula $P=2l+2w$ and solve for "w":

$58=2(\frac{201.25}{w})+2w\\\\58=\frac{402.5}{w}+2w\\\\58=\frac{402.5+2w^2}{w}\\\\58w=402.5+2w^2\\\\2w^2-58w+402.5=0$

Applying the Quadratic formula $x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$ , we get:

$x=w=\frac{-(-58)\±\sqrt{(-58)^2-4(2)(402.5)}}{2(2)}\\\\w_1=17.5\\\\w_2=11.5$

3. Substitute $w_1=17.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{17.5}=11.5$

4. Substitute $w_2=11.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{11.5}=17.5$

Therefore, since the value of the lenght of a rectangle must be greater that the value of the width, we can conclude that the lenght and the width of the rectangular baking sheet are:

$l=17.5\ in\\\\w=11.5\ in$