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3 years ago

0.199 to the nearest hundredth.

1 answer:

6 0

0.20 would be the answer.
The number places on a number go as follows starting at 0. and going to the right
ones, tenths, hundredth
This means that 0.00 is the hundredth place (the bolded 0). Since you round a 9 up one, this makes the 1 in the tenths place go to a 2 and the hundredth go to a 0

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in the second half of the game, the Wildcats again scored 18 points. This time, however, we don't know how many total shots were

Kobotan [32]

Lets start with the chain of 3's:

18 = 3 + 3 + 3 + 3 + 3 + 3

But, we know that

3 + 3 = 2 + 2 + 2

Sol, let's replace 3 + 3 by 2 + 2 + 2 one by one.

Hence, the possible ways of combinations are listed below:

18 = 3 + 3 + 3 + 3 + 2 + 2 + 2 (1)

18 = 3 + 3 + 2 + 2 + 2 + 2 + 2 + 2 (2)

Therefore, there are two combinations of 2- and 3- point shots that could total 18 points.

3 0

3 years ago

A car dealership sold 850 cars last year. This year the dealership sold 715 cars. What is the percent decrease, to the nearest p

Bumek [7]

The answer is 16%

Hope this helps :)

3 0

2 years ago

Read 2 more answers

CALC- limits please show your method

gladu [14]

A. Factor the numerator as a difference of squares:

$\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6$

c. As $x\to\infty$ , the contribution of the terms of degree less than 2 becomes negligible, which means we can write

$\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4$

e. Let's first rewrite the root terms with rational exponents:

$\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}$

Next we rationalize the numerator and denominator. We do so by recalling

$(a-b)(a+b)=a^2-b^2$
$(a-b)(a^2+ab+b^2)=a^3-b^3$

In particular,

$(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3$
$(x^{1/2}-x)(x^{1/2}+x)=x-x^2$

so we have

$\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}$

For $x\neq0$ and $x\neq1$ , we can simplify the first term:

$\dfrac{x-x^3}{x-x^2}=\dfrac{x(1-x^2)}{x(1-x)}=\dfrac{x(1-x)(1+x)}{x(1-x)}=1+x$

So our limit becomes

$\displaystyle\lim_{x\to1}\frac{(1+x)(x^{1/2}+x)}{x^{2/3}+x^{4/3}+x^2}=\frac{(1+1)(1+1)}{1+1+1}=\frac43$

3 0

3 years ago

Jamie and Stella are saving money to sign up for a school trip to Washington, D.C. In order to sign up for the trip, they must p

sveticcg [70]

Answer:

Part 1: 25x ≥ 600

Part 2: 15y ≥ 600

Part 3: y ≤ 40

Explanation:

Verbal statements must be translated into algebraic expressions, equations or inequalities.

1. Money earned by Jamie washing cars for $25 each

Let x represent the number of cars Jaime washes.

2. Money earned by Stella making pecan pies for $15 each

Let y represent the number of pies she makes

3. Constraint on the number of pies that Stella can make because she only has enough supplies to make 40 pies.

Write an inequality using the symbol ≤, since y can take any integer value up to 40.

y ≤ 40

4. First question:

Part 1: Write a constraint (an inequality) to represent how much money Jamie needs for his trip

25x ≥ 600

5. Second question:

Part 2: Write a constraint (an inequality) to represent how much money Stella needs for her trip.

15y ≥ 600

6. Third question

Part 3: Write a constraint (an inequality) to represent the limitations of Stella's supplies.

From step # 3

y ≤ 40

7. Conclusion

You can solve the inequalities fo find whether Stella can or not afford the trip:

Solve for the inequalities that represent Stella's situation:

15y ≥ 600

y ≥ 600 / 15

y ≥ 40

From step 6: y ≤ 40

The solution set is the intersection of the two solutions:

y ≥ 40 ∩ y ≤ = 40 = 40.

Interpretation: Stella will be able to make 40 pies, which represents a revenue of $ 15 / pie × 40 pie = $ 600, so she will be able to make the trip.

6 0

3 years ago

What is the density of 72g over 24cm?

diamong [38]

Mass/volume 72g/24 cubic cm Is equal to 3G per cubic centimeter

5 0

2 years ago