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3 years ago

A group of 15 people were surveyed about the month they were

Mathematics

2 answers:

Nadya [2.5K]3 years ago

8 0

Yeah I don’t know yeah I don’t know why you don’t like it but I’m not a

Sergio [31]3 years ago

6 0

Only 1 person was born in March

3/5ths of 15 people is 9 people and 1/3rds of 15 people is 5 which totals to 14 meaning there is only 1 person left to be born in March

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A ball is thrown into the air with an initial upward velocity of 46ft/s. Its height (h) in feet after t seconds is given by the

Misha Larkins [42]

The answer is A: 3 feet; this answer can be obtained by finding the zeros of the equation above.

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3 years ago

Hank is buying new curtains for his house. Each window will need 2 curtains panels to cover it. He has a total of 16 windows in

fenix001 [56]

Answer:

He spends $298

Step-by-step explanation:

He has 16 curtains

16*2=32

That answer is how many he needs

Now multiply that by the price

32 curtains for $29

32*29=928

The answer is $928

5 0

3 years ago

Read 2 more answers

Help! I will give brainliest!

alekssr [168]

Answer:

B 24

Step-by-step explanation:

3/5 is 54°

1/3 is 30°

54-30 = 24

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3 years ago

What is the solution of

kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

$\sqrt{2x+4}-\sqrt{x}=2$

Isolating √(2x+4): Addind √x both sides of the equation:

$\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}$

Squaring both sides of the equation:

$(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}$

Simplifying on the left side, and applying on the right side the formula:

$(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}$

$2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x$

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

$2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}$

Squaring both sides of the equation:

$(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x$

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

$x^{2}-16x=16x-16x\\ x^{2}-16x=0$

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2$

x=0 is a solution

2) x=16

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2$

x=16 is a solution

Then the solutions are x=0 and x=16

5 0

3 years ago

The expression when m=6 and n=4

AlladinOne [14]

Plugging in the values, we get 7(6)-4=42-4=38.

3 0

3 years ago

Read 2 more answers