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yuradex [85]
3 years ago
7

What substance is removed from the air by living things for respiration?

Chemistry
2 answers:
seropon [69]3 years ago
8 0

Answer:

If i'm correct it is carbon dioxide. If i'm not correct sorry!

Explanation:

Basile [38]3 years ago
7 0

Answer:

Carbon dioxide

Explanation:

Living objects breathe because they need to obtain oxygen to carry out cellular respiration to stay alive, just like plants need to respire to stay alive. Then byproducts such as carbon dioxide and water are released and removed from the living objects through breathing, just like plants do when they respire.

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A 65.0-gram sample of some unknown metal at 100.0° C is added to 100.8 grams of water at 22.0° C. The temperature of the water r
vampirchik [111]
We do a heat balance to solve this:
(m cp ΔT)water = -(m cp ΔT)metal
100.8 (4.18) (27 - 22) = -65 (cp)(27-100)
cp = 100.8 (4.18) (27 - 22) / (-65 (27-100))
cp = 0.44 J/ (°C × g)

The specific heat of the metal is 0.44 J/ (°C × g)
5 0
3 years ago
Which law relates to the ideal gas law?​
ella [17]

Answer:

equation (4.16) depends on Boyle's law and Charles' law. The above relates the adjustment in perfect gas volume to the progressions in winning weight and temperature, separately. Moreover, equation (4.16) is alluded to as the condition of state for a perfect gas.

hope it helps:))

4 0
3 years ago
What is the mass of an atom that has 9 protons, 11 neutrons, and 10 electrons
Anastaziya [24]

Answer: By looking at the periodic table, you will see that Fluorine has 9 protons. Since the number of electrons equal the number of protons, Fluorine has 9 electrons as well. Meanwhile, it's mass number of 19, minus 10 neutrons, gives you 9 protons or electrons. Hence, the atom would be Fluorine.

Explanation:

6 0
2 years ago
Read 2 more answers
Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and
blondinia [14]

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g;     Hydrogen H = 2.24 g     Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon

For Hydrogen:

=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen

For Oxygen:

=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon

For Hydrogen:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen

For Oxygen:

\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen

Thus, the empirical formula is HCO₂

4 0
3 years ago
A solution contains 11% by mass of sodium chloride. this means that __________.
d1i1m1o1n [39]

As a solution is contained with 11% by mass of sodium chloride, this will therefore conclude that the 100g of the solution is composed of the 11g of the sodium chloride. In which, the correct answer would be specified as letter c.

5 0
3 years ago
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