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Gwar [14]
4 years ago
7

el volumen de un cubo es de 125 cm3 ¿ cuantas veses aumentara el volumen de ese cubo si se duplica la medida de su arista

Mathematics
1 answer:
Vinil7 [7]4 years ago
5 0

Answer: 8 times.

Step-by-step explanation:

I will answer in English:

This says:

The volume of a cube is 125cm^3

How many times the volume will increase if we duplicate the lenght of the side?

If L is the lenght of the side, we have that the volume of the cube is:

V = L^3

If we duplicate the lenght of the side, the new volume is:

V = (2*L)^3 = 8*L^3

So we can see that the volume of the new cube is 8 times the volume of the previous cube.

Now,  we can do the math, for our original cube we have:

L^3 = 125cm^3

L = 5cm

the new cube has L' = 2*L = 10cm

The volume of this cube is:

V' = L'^3 = 10cm^3 = 1000cm^3

the ratio V'/V is:

1000cm^3/125cm^3 = 8

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Answer:

Option D - Will not be rejected at the 0.05 level.

Step-by-step explanation:

The significance level, which is denoted as "α", is a measure of the strength of the evidence that must be present in a sample before we can reject the null hypothesis and conclude that the effect is statistically significant. Now, this significance level must be determined before conducting an experiment.

Now, in the context of this question, the significance level is the probability of rejecting the null hypothesis when it is true. For example, a significance level of 0.05 means a 5% risk of concluding that a difference exists when there is no actual difference. Now, lower significance levels will indicate that we require stronger evidence before we can reject the null hypothesis.

Thus, if we don't reject at α = 0.1,we obviously will not reject at higher values.

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3 years ago
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BigorU [14]

Answer:

-25

Step-by-step explanation:

Evaluate -x - 6 x + 10 where x = 5:

-x - 6 x + 10 = -5 - 6×5 + 10

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10 - (5 + 30)

5 + 30 = 35:

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10 - 35 = -(35 - 10):

-(35 - 10)

| 3 | 5

- | 1 | 0

| 2 | 5:

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We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!

We are given with ;

{:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}

Take LCM on both sides :

{:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}

<em>Multiplying</em> both sides by <em>10</em> ;

{:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}

{:\implies \quad \sf 165+6y=7y+150}

Can be <em>further written</em> as ;

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Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>

{:\implies \quad \sf 7y-6y=165-150}

{:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}

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