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4 years ago

If a net force of 800n is acting on an object with a mass of 60kg. What would be the objects accelerations

Physics

1 answer:

aivan3 [116]4 years ago

5 0

Answer: 13.33 m/s^2

Explanation:

Force is the product of mass of an object and its acceleration.

i.e Force = Mass x Acceleration

Since Force on object = 800N

Mass of object = 6Kg

Acceleration = ?

Then, Force = Mass x Acceleration

800N = 60Kg x Acceleration

Acceleration = (800N/60kg)

Acceleration = 13.33 m/s^2 (The unit of acceleration is metre per second square)

Thus, the objects accelerations is 13.33 m/s^2

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A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of

balandron [24]

Answer:

The skater covers a distance of <u>15 m</u> before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

$f=\mu N$

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, $N=mg$

∴ $f=\mu mg=0.490\times 90\times 9.8=432.18\ N$

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

$W=-fd=-432.18d$

Now, change in kinetic energy is given as:

$\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J$

Therefore, from work-energy theorem,

$W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m$

Hence, the skater covers a distance of 15 m before stopping.

7 0

3 years ago

Please help :/ The same motor is used in rockets with different masses. The rockets have different accelerations. According to N

Ymorist [56]

Answer:

1. As rocket mass increases, acceleration decreases.

2. The inverse of the mass of the boat.

Explanation:

1. Newton's second law of motion states;

F = ma

where F is the force applied, m is the mass and a is the acceleration.

Therefore, increasing the mass of a rocket increases its weight which would reduce its acceleration provided that the force is constant. Thus, as rocket mass increases, acceleration decreases.

2. The slope of the graph can be expressed as;

From Newton's second law,

F = ma

Slope = (Δa) ÷ (ΔF)

Slope = $\frac{a}{F}$

⇒ $\frac{1}{m}$ = $\frac{a}{F}$

Therefore, the slope of the graph is the reciprocal of the mass of the boat.

7 0

4 years ago

The movement of water is able to transport minerals and nutrients. Which statement best explains why water is able to do this?

Marrrta [24]

no it can't do this why because I think that it is water and it can not go any where.

3 0

3 years ago

Read 2 more answers

Is this statement true or false?

RSB [31]

Answer:

Places at the same latitude may have very different climates if one is on a coast and one is inland. On the coast, the climate is influenced by warm moist air from the ocean. A coastal climate is usually mild. ... Farther inland, the climate is influenced by cold or hot air from the land.

Explanation:

Hopefully its correct!

8 0

3 years ago

Read 2 more answers

Suppose two point charges, Q1 = -6.25 x 10-9 C and Q2 = -6.25 x 10-9 C, are separated by a distance d = 0.617 m.

n200080 [17]

Answer:

The answer to your question is the letter A) F = 9.23 x 10⁻⁷ N

Explanation:

Data

q₁ = -6.25 x 10⁻⁹ C

q₂ = -6.25 x 10⁻⁹ C

d = 0.617 m

k = 9 x 10⁹ Nm²/C²

F = ?

Formula

F = k q₁q₂ /r²

-Substitution

F = (9 x 10⁹)(-6.25 x 10⁻⁹)(-6.25 x 10⁻⁹) / (0.617)²

-Simplification

F = 3.512 x 10⁻⁷ / 0.381

-Result

F = 9.227 x 10⁻⁷ N ≈ 9.23 x 10⁻⁷ N

8 0

3 years ago