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madreJ [45]
3 years ago
14

An object will maintain a constant speed until a force acts on it true or false

Physics
1 answer:
Scorpion4ik [409]3 years ago
3 0
<span>You do not require a force to keep something moving.  You only require a force to get it moving.  Or to stop it moving.  In your everyday experiences, something you get moving seems to come to a stop after you stop pushing it.  It is because there are forces (friction) that make it stop.  Without those forces, the object would just keep moving. So this would mean the answer would be True.</span>
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Transformation of Energy

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Suppose a metal sphere is launched up a ramp with Vi=1.5 m/s. The end of the ramp is 1.20 m above the floor. The ramp is at an a
Mekhanik [1.2K]
The sphere will go up until all the initial kinetic energy be transformed into potential energy.

Intital kinetic energy = m*(vi)^2 / 2


Final potential energy = mgh

mgh = m(vi)^2 / 2 => h = (vi)^2 / (2g)

g = 9.81 m/s^2
vi = (1.5m/s)^2

h = (1.5m/s)^2 / (2*9.81m/s)^2 = 0.115 m

The range is the distance run over the ramp

Using trigonometry, sin(20°) = h /run => run = h / sin(20) = 0.115m / sin(20) = 0.336 m

Answer: 0.336 m
3 0
4 years ago
At a certain distance from the center of the Earth, a 0.4-kg object has a weight of 2.0 N. (a) Find this distance. (b) If the ob
Alika [10]

Answer:

a) The distance of the object from the center of the Earth is 8.92x10⁶ m.

b) The initial acceleration of the object is 5 m/s².

Explanation:

a) The distance can be found using the equation of gravitational force:

F = \frac{GMm}{r^{2}}

Where:

G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²

M: is the Earth's mass =  5.97x10²⁴ kg  

m: is the object's mass = 0.4 kg

F: is the force or the weight = 2.0 N    

r: is the distance =?

The distance is:

r = \sqrt{\frac{GMm}{F}} = \sqrt{\frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.97 \cdot 10^{24} kg*0.4 kg}{2.0 N}} = 8.92 \cdot 10^{6} m      

Hence, the distance of the object from the center of the Earth is 8.92x10⁶ m.

         

b) The initial acceleration of the object can be calculated knowing the weight:              

W = ma                                                  

Where:            

W: is the weight = 2 N

a: is the initial acceleration =?          

a = \frac{W}{m} = \frac{2 N}{0.4 kg} = 5 m/s^{2}

Therefore, the initial acceleration of the object is 5 m/s².

           

I hope it helps you!    

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