The sphere will go up until all the initial kinetic energy be transformed into potential energy.
Intital kinetic energy = m*(vi)^2 / 2
Final potential energy = mgh
mgh = m(vi)^2 / 2 => h = (vi)^2 / (2g)
g = 9.81 m/s^2
vi = (1.5m/s)^2
h = (1.5m/s)^2 / (2*9.81m/s)^2 = 0.115 m
The range is the distance run over the ramp
Using trigonometry, sin(20°) = h /run => run = h / sin(20) = 0.115m / sin(20) = 0.336 m
Answer: 0.336 m
Answer:
a) The distance of the object from the center of the Earth is 8.92x10⁶ m.
b) The initial acceleration of the object is 5 m/s².
Explanation:
a) The distance can be found using the equation of gravitational force:

Where:
G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²
M: is the Earth's mass = 5.97x10²⁴ kg
m: is the object's mass = 0.4 kg
F: is the force or the weight = 2.0 N
r: is the distance =?
The distance is:
Hence, the distance of the object from the center of the Earth is 8.92x10⁶ m.
b) The initial acceleration of the object can be calculated knowing the weight:
Where:
W: is the weight = 2 N
a: is the initial acceleration =?

Therefore, the initial acceleration of the object is 5 m/s².
I hope it helps you!
Aerospace engineering is responsible for a plane design