Answer:
According to Newton's Second Law of Motion :
Where,
F = Force Applied
m = Mass of the object
a = Acceleration
Now, we will use this law to solve this question.
Given :
Acceleration or a = 15.3 m/s²
Force = 44 N
Mass = ?
Substitute, the given values in the formula.
F = ma
⇒ m = F/a
m = 44/15.3
<u>m = 2.9 kg</u>
When plates pull apart underwater, the hot magma instantly rises and spreads itself to form a new ocean floor.Under a continent, the crust splits open to allow magma out. The magma might make its way slowly to the surface, creating warm areas and hot springs or geysers as surface water meets it.<span>Or the magma might explode, bringing into existence a new volcano where there was only cool earth before.</span>
Answer:
beam of light converges to a point A. A lens is placed in the path of the convergent beam 12 cm from P.
To find the point at which the beam converge if the lens is (a) a convex lens of focal length 20 cm, (b) a concave lens of focal length 16 cm
Solution:
As per the given criteria,
the the object is virtual and the image is real (as the lens is placed in the path of the convergent beam)
(a) lens is a convex lens with
focal length, f=20cm
object distance, u=12cm
applying the lens formula, we get
f
1
=
v
1
−
u
1
⟹
v
1
=
f
1
+
u
1
⟹
v
1
=
20
1
+
12
1
⟹
v
1
=
60
3+5
⟹v=7.5cm
Hence the image formed is real, at 7.5cm from the lens on its right side.
(b) lens is a concave lens with
focal length, f=−16cm
object distance, 12cm
applying the lens formula, we get
f
1
=
v
1
−
u
1
⟹
v
1
=
f
1
+
u
1
⟹
v
1
=
−16
1
+
12
1
⟹
v
1
=
48
−3+4
⟹v=48m
Hence the image formed is real, at 48 cm from the lens on the right side.
The moon is thought to have an iron-rich core whose radius
is 330 km, plus or minus an uncertainty of 20 km.
That puts its diameter in the range of 620 km to 700 km.
Answer:
Explanation:
a) the acceleration of the puck on the rough ice.
a = μg = 0.550(9.81) = 5.3955 = 5.40 m/s²
(comes from μ = F/N = ma/mg = a/g)
b) the distance from the end boards the puck is when it comes to a stop.
v² = u² + 2as
0² = 12.0² + 2(-5.40)s
s = 13.3 ft
so distance from the boards is
15.7 - 13.3 = 2.4 m
by the way...that's some VERY rough ice...more like sand.
