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mina [271]
3 years ago
7

Explain the importance of having a support network when trying to achieve a healthy lifestyle. Who supports you when it comes to

making healthy nutrition and exercise choices? Do you have a role model you look up to when it comes to fitness? What do you have to do in order to become a role model for your community members?
(essay)
Physics
2 answers:
Vadim26 [7]3 years ago
7 0

Answer:

Who are the people for you then I can help you format the essay

Explanation:

Eva8 [605]3 years ago
4 0

Answer:

This is my essay!!!

Explanation:

Only 2.7 percent of Americans live a healthy lifestyle. We need individuals who listen to us and give us truthful feedback. Research has shown that there are many beneficial advantages of providing a support net, such as higher levels of well-being, improved coping skills, and longer and healthier life. Studies have also shown that depression and anxiety can be minimized by social support. Some individuals perform well with a broad support network, while others prefer a small system of support. It is a basic human need to provide and obtain assistance from others.

My mom is the best supporter when it comes to health and exercise choices. She will tell me that I need to start eating healthy and say you can do this, and put your mind to it. I will want to drink a soda one day and she will take it away and give me water so she can encourage me to start drinking more water, because of that I drink water every day and eat much healthier. I am so glad that she supports me and my choices.

That would be a yes. her name is Chloe ting. She uploads fitness videos and she is my biggest role model. She has the best exercise videos. Her videos inspire me to keep going every day and to not give up, she is so amazing. She has different types of videos like 2-week fitness, and lose fat in less than a week, etc. But I always watch her videos and try to do one every day.

If I were to become a role modal I would work hard every day. Making sure I am healthy and tell people that if they want to change how they look that I am with them and that they should never give up no matter what, know that they can do it. People always give up because it gets too hard but I have been there too, but I never gave up because I know that I could do it. I know I would succeed. You just have to know that you can do it.

Do you have someone who supports you? Do you have a supermodel? What would you do if you were to become a role model? Talking about this really encouraged me that I should keep going till I'm satisfied. You should know that your strong and you can do it, but you have to try.

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According to Coulomb's law, the force of attraction or repulsion between two charges is
Maru [420]

Answer:

B is the answer

Explanation:

thank you I hope it helps you

6 0
3 years ago
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A basketball weighing 0.63 kg is dropped from a height of 6.0 meters onto a court. Use the conservation of energy equation to de
frutty [35]

Answer:

The velocity of the ball at a height of 2.0 meters above the court is approximately 8.85 m/s

Explanation:

The given parameters of the ball are;

The mass of the ball, m = 0.63 kg

The height from which the ball is dropped, h₁ = 6.0 meters

The height at which the velocity of the ball is sought, h₂ = 2 meters

The initial potential energy of the ball, P.E. = m·g·h₁ = 0.63 × 9.8 × 6.0  = 37.044

The initial potential energy of the ball, P.E.₁ = 37.044 J

The potential energy of the ball, when the ball is at 2 meters above the court, P.E.₂ = m·g·h₂ = 0.63 × 9.8 × 2.0 = 12.348

The potential energy of the ball, when the ball is at 2 meters above the court, P.E.₂ = 12.348 J

From M.E> = P.E. + K.E.

Where;

M.E = The total mechanical energy of the ball = Constant

P.E. = The potential energy of the ball

K.E. = The kinetic energy of the ball

By the conservation of energy principle, we have;

The potential energy lost by the ball = The kinetic energy gained by the ball

The potential energy lost by the ball = P.E.₁ - P.E.₂ = 37.044 - 12.348 = 24.696

The potential energy lost by the ball = 24.696 J

The kinetic energy gained by the ball = 1/2·m·v² = 1/2×0.63×v²

Where;

v = The velocity of the ball

∴ The potential energy lost by the ball at 2.0 meters above the court = 24.696 J = The kinetic energy gained by the ball at 2.0 meters above the court = 1/2×0.63×v²

24.696 J = 1/2×0.63 kg ×v²

v² = 24.696 J / (1/2×0.63 kg) = 78.4 m²/s²

∴ v = √(78.4 m²/s²) = 8.85437744847 m/s

The velocity of the ball at a height of 2.0 meters above the court, v ≈ 8.85 m/s.

7 0
3 years ago
Give the number of protons (p), electrons (e), and neutrons (n) in one atom of nickel-62. A) 28 p, 28 e, 28 n B) 28 p, 28 e, 34
Reika [66]
<h2>Option B is the correct answer.</h2>

Explanation:

We need to find number of protons, electrons and neutrons in ⁶²Ni

Mass number is 62.

That is

       Number of proton + Number of neutron = 62

We know that number of proton = 28 for nickel

So

       28 + Number of neutron = 62        

        Number of neutron = 62 - 28 = 34

We also know

         Number of protons = Number of electrons

          Number of electrons = 28

Option B is the correct answer.

3 0
3 years ago
What does it mean to dissolve something
melamori03 [73]
Mixing something into a liquid to create a solution. 
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Dennis_Churaev [7]

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<h3>Unpolarized light:</h3>

Unpolarized light is diminished by a factor of ½ when it travels through a polarizer. Cos 2θ averages out across all angles to be ½ in size. I transmitted = I₀ and ½ I₀ at all angles The unpolarized light's intensity decreases to zero.

The light-producing atoms on the heated filament's surface behave independently of one another. Each of these emissions can be roughly represented as a brief "wave train" lasting between approximately 109 and 108 seconds. These wave trains, each with its unique polarization direction, are superimposed to form the electromagnetic wave that is coming from the filament.

Unpolarized light is produced by all common light sources, including the Sun, incandescent and fluorescent lighting, and flames.

Learn more about unpolarized light here:

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