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2 years ago

I need help with number 9, plz help me

Mathematics

1 answer:

Nuetrik [128]2 years ago

7 0

I can’t see the whole question, so i tried to answer as much as i could think of

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How can completing the square aid in solving quadratic functions?

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Completing the squares tells us exactly what square root we will need to calculate our answer.

Using the formula below you can find these answers:
$A(x-h)^2 + K = 0
(x-5)^ 2 = - K/A
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Does this make sense?

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3 years ago

Let a = 3; x = 2<br><br>c) y = ( a * x ) * x * ( x + 7 )

Molodets [167]

Step-by-step explanation:

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3 years ago

What number should go in box A on this number line? 4. 5. A

cestrela7 [59]

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Step-by-step explanation:

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2 years ago

-7(-2a+6)=2a-6(-a+7)

Alenkinab [10]

Answer:

$a=0$

Step-by-step explanation:

$-7(-2a+6)=2a-6(-a+7)$

$14a-42=2a+6a-42$

$14a-42=8a-42$

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3 years ago

What are the coordinates of the circumcenter of this triangle?

Oduvanchick [21]

Answer:

The coordinates of the circumcenter of this triangle are (3,2)

Step-by-step explanation:

we know that

The circumcenter is the point where the perpendicular bisectors of a triangle intersect

we have the coordinates

$A(-2,5),B(-2,-1),C(8,-1)$

step 1

Find the midpoint AB

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

substitute the values

$M=(\frac{-2-2}{2},\frac{5-1}{2})$

$M_A_B=(-2,2)$

step 2

Find the equation of the line perpendicular to the segment AB that passes through the point (-2,2)

Is a horizontal line (parallel to the x-axis)

$y=2$ -----> equation A

step 3

Find the midpoint BC

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

substitute the values

$M=(\frac{-2+8}{2},\frac{-1-1}{2})$

$M_B_C=(3,-1)$

step 4

Find the equation of the line perpendicular to the segment BC that passes through the point (3,-1)

Is a vertical line (parallel to the y-axis)

$x=3$ -----> equation B

step 5

Find the circumcenter

The circumcenter is the intersection point between the equation A and equation B

$y=2$ -----> equation A

$x=3$ -----> equation B

The intersection point is (3,2)

therefore

The coordinates of the circumcenter of this triangle are (3,2)

3 0

2 years ago