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NISA [10]
3 years ago
12

1. Find the area of the figure below. s=25 m

Mathematics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

625m

Step-by-step explanation:

The area is equal to l times w, so since the length and width are the same value you would do 25 x 25 which gets you to 625

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Use the coordinates of the plotted points to complete the calculation below. Pay attention to negative signs.
MArishka [77]

Answer:

  • 3
  • 1
  • -3
  • 1
  • -3

Step-by-step explanation:

The <em>change in y</em> is the difference in y-coordinates between the lower right point and the upper left point. Similarly, the <em>change in x</em> is the difference in the x-coordinates of those points.

  \text{Slope}=\dfrac{\text{change in y}}{\text{change in x}}=\dfrac{\boxed{3}-6}{2-\boxed{1}}\\\\=\dfrac{\boxed{-3}}{\boxed{1}}\\\\\\=\boxed{-3}

7 0
3 years ago
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school guidelines require that there must be atleast 2 chaperones for every 25 students going on a school trip.how many chaperon
Anna007 [38]

Answer:

there must be at least 6 chaperones

Step-by-step explanation:

25 x 3= 75 so 2 chaperons x 3= 6 with a remainder of 5 students

5 0
3 years ago
Write the decimal number in words 235.678
ValentinkaMS [17]
Two hundred thirty-five and six hundred seventy-eight thousandths
3 0
3 years ago
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For the cyclic quadrilateral ABCD, which statement is true? A) The sum measure of ∠A and ∠B equals 180°. B) The sum measure of ∠
kifflom [539]
See the picture attached to better understand the problem

we know that
A quadrilateral is called Cyclic quadrilateral <span>if its all vertices lie on the circle.
</span><span>The opposite angles of a Cyclic - quadrilateral are supplementary
</span>so
∠A+∠C=180°
and
∠B+∠D=180°

therefore
the answer is
<span>C) The sum measure of ∠B and ∠D equals 180°</span>

6 0
3 years ago
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In a race in which eleven automobiles are entered and there are no ties, in how many ways can the first three finishers come in?
viva [34]

Answer:

990 ways

Step-by-step explanation:

The total number of automobiles we have is 11.

Now, what this means is that for the first position , we shall be selecting 1 out of 11 automobiles, this can be done in 11 ways( 11C1 = 11!/(11-1)!1! = 11!/10!1! = 11 ways)

For the second position, since we have the first position already, the number of ways we can select the second position is selecting 1 out of available 10 and that can be done in 10 ways(10C1 ways = 10!9!1! = 10 ways)

For the third position, we have 9 automobiles and we want to select 1, this can be done in 9 ways(9C1 ways = 9!/8!1! = 9 ways)

Thus, the total number of ways the first three finishers come in = 11 * 10 * 9 = 990 ways

8 0
3 years ago
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