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3 years ago

Please help me on this

Mathematics

1 answer:

vfiekz [6]3 years ago

4 0

9514 1404 393

Answer:

y = 25, 17, 13, 5 . . . . (top-down order)

Step-by-step explanation:

Put the values of x in the expression for y and do the arithmetic.

y = 29 - 4×1 = 25

y = 29 - 4×3 = 17

y = 29 - 4×4 = 13

y = 29 - 4×6 = 5

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

For the funtion f(x)= (x+7)^5, Find f^-1 (x)

quester [9]

Answer:

The inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

Step-by-step explanation:

For the function $f(x)= (x+7)^5$ , Find $f^{-1} (x)$

For finding inverse of x,

First let:

$y=(x+7)^5$

Now replace x with y and y with x

$x=(y+7)^5$

Now, solve for y

Taking 5th square root on both sides

$\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7$

Now, replace y with $f^{-1} (x)$

$f^{-1} (x)=\sqrt[5]{x}+7$

So, the inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

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3 years ago

8. A substance has a half life of 2.347 minutes.

mina [271]

Answer:

a.) 4 half lives have passed

b) 9.388 minutes

Step-by-step explanation:

Formula for exponential growth / decay is given as:

$A=A_0b^{\frac{t}{c}}$

Where $A$ is the final population

$A_0$ is the initial population

$b$ is the growth factor

$c$ is the time taken for the growth 'b'

$t$ is the amount of time

Here, we are given that:

$A$ = 6. 9 grams

$A_0$ = 110.4 grams

$b = \dfrac{1}{2}$

$c = 2.347$ min

To find:

a.) Number of half lives taken for the decay.

b.) Total time in the decay.

Solution:

a.) Number of half lives taken for the decay is nothing but equal to $\frac{t}{c}$ .

Putting the values in the formula, we get:

$6.9=110.4\times \frac{1}2^{\frac{t}{c}}\\\Rightarrow 6.9=110.4\times 0.5^{\frac{t}{c}}\\\Rightarrow 0.0625=0.5^{\frac{t}{c}}\\\Rightarrow \dfrac{t}{c} =4$

Therefore, the answer is:

<em>4 half lives </em>have passed.

b.) Total time of decay. We have to find the value of $t$ here.

From answer of part a.):

$\dfrac{t}{c} =4\\\Rightarrow \dfrac{t}{2.347} =4\\\Rightarrow t =\bold{9.388\ min}$

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3 years ago