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mr_godi [17]
3 years ago
7

-0.18 divied by 0.03

Mathematics
1 answer:
postnew [5]3 years ago
6 0
Answer:
-6

Explanation: use a calculator lol


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What is the answer to A and B?
Alex_Xolod [135]
For A) u must start at -3 on y lines. Then move points up 1 and 3 to the right. Makes point and continue to make lines
For B) start at 5 on y lines, and remember -x is same thing is -1. And negative means go down! So move 1 down and 1 to the right and make point then move 1 down and make 1 right and make second points and continue. Draw a lines.

The solution is when u see two lines from two equations crosses to each other. There’s solution shown.
3 0
4 years ago
22. Write the following as fractions: <br><br>i) Seven hundredths<br> ii) Six ninths​
Brilliant_brown [7]
Here are both in fraction form.

i) 7/100
ii) 6/9
3 0
3 years ago
What the heck do i put here pls help
Genrish500 [490]

Answer:

I can't answer the whole question but the first one is 7 x 9, or 63 squares. And say you chose a square that is 4 x 3 so that would be the area of the tile you chose. Im sorry I couldn't answer the whole thing but I hope that makes since of what I did, if not please ask questions.

Step-by-step explanation:

5 0
3 years ago
(5x-25)+(3x+9)=180 please answer right now
jok3333 [9.3K]

Answer:

x=24.5\\

Step-by-step explanation:

So we have the equation:

(5x-25)+(3x+9)+180

Combine like terms:

(5x+3x)+(-25+9)=180

Add:

8x-16=180

Add 16 to both sides:

8x=196

Divide both sides by 8:

x=24.5\\

So, our answer is 24.5 :)

6 0
3 years ago
Assume that IQ scores are normally distributed with a mean of 100 and a standard deviation of 16. If 100 people are randomly sel
laiz [17]

Answer:

0.03 is  the probability that for the sample mean IQ score is greater than 103.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 16

Sample size, n = 100

We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

\dfrac{\sigma}{\sqrt{n}} = \dfrac{16}{\sqrt{100}} = 1.6

P( mean IQ score is greater than 103)

P(x > 103)

P( x > 103) = P( z > \displaystyle\frac{103 - 100}{1.6}) = P(z > 1.875)

= 1 - P(z \leq 1.875)

Calculation the value from standard normal z table, we have,  

P(x > 103) = 1 - 0.970 =0.03= 3\%

0.03 is  the probability that for the sample mean IQ score is greater than 103.

7 0
3 years ago
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