Hi there!
We can find the range using completing the square:
y = -x² - 2x + 8
Factor out a -1:
y = -(x² + 2x) + 8
Use the first two terms. Take the second term's coefficient, divide by 2, and square:
y = -(x² + 2x + 1) + 8
Remember to add by 1 because we cannot randomly add an additional number into the equation:
y = -(x² + 2x + 1) + 8 + 1
Simplify:
y = -(x + 1)² + 9
Since the graph opens downward (negative coefficient), the range is (-∞, 9)
Answer with Step-by-step explanation:
We are given that a point (3,1,0)
Two vectors are
A=<1,1,0>
B=<0,1,1>
Let v
Substitute the values then we get
The parametric equation of the line
Using the formula
The parametric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by
The symmetric equation of the line is given by
Using the formula
The symmetric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by