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3 years ago

The large number before a molecule in a chemical formula is called a _______________.

Chemistry

2 answers:

Alexxandr [17]3 years ago

7 0

Answer:

Subscript

Explanation:

The little number you see to the right of the symbol for an element is called a subscript. That number indicates the number of atoms of that element present in the compound. When balancing an equation, you can change the coefficients but not the subscripts.

hope this helps! if not, it's got to be coefficient or equation

Komok [63]3 years ago

5 0

The answer is coefficient

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2 years ago

Complete the balanced equation: Cu(NO3)2 + Na2CO3 > ?

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3 years ago

A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h

Ksenya-84 [330]

Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution : 0.0328 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0328=\frac{\text{Number of moles}}{0.250 L}$

Moles of HCl in 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution : 0.0245 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}$

Moles of NaOH in 0.100 L solution = 0.00245 moles

3) Concentration of hydrochloric acid in the resulting solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.

Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L

Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles = 0.00575 moles

$Molarity=\frac{\text{number of moles}}{\text{volume of solution in L}}$

Molarity of HCl left un-neutralized : $\frac{0.00575 moles}{0.350L}=0.0164 M$

0.0164 molar concentration of hydrochloric acid in the resulting solution.

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3 years ago

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Assoli18 [71]

Lighting a match changes chemical energy into heat.

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3 years ago

If there is 18.0 g of Cl2 gas at a temperature of 348 K and a pressure of 177 kPa, what is the volume of the Cl2 gas?

gtnhenbr [62]

The volume of the Cl₂ gas is 4.15 L.

Explanation:

This problem can be easily solved using the ideal gas law.

As in ideal gas law, it is stated that the product of pressure and volume is equal to the product of number of moles with temperature with gas constant.

PV=nRT

So, in the present case, pressure P is given as 177 kPa, temperature T = 348 K and the mass of chlorine gas is given as 18 g.

So first step, we have to determine the value of 'n' using the mass of Chlorine gas given. The mass should be converted to moles by dividing the mass with molar mass of the gas.

$n = \frac{Mass}{Molar mass}$

As molar mass of Cl is 35.453 g/mol, then $Molar mass of Cl_{2} = 2 * 35.453 = 70.906 g/mol$

So, $n = \frac{18 g}{70.906 g/mol} =0.254 moles$

Then, the volume can be determined with R = 8.3144×10³ L Pa K⁻¹ mol⁻¹ as shown below:

$V = \frac{nRT}{P} =\frac{0.254*8.3144*10^{3} *348}{177*10^{3} } =4.15 L$

Thus, the volume of the Cl₂ gas is 4.15 L.

7 0

3 years ago