Which would be attracted most to a magnet?
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In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.
Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.
For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.
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Answer:
The standard cell potential of the reaction is 0.78 Volts.
Explanation:
Reduction at cathode :
Reduction potential of to Cu=
Oxidation at anode:
Reduction potential of to Fe=
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
The standard cell potential of the reaction is 0.78 Volts.