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vazorg [7]
2 years ago
13

Look at this list of numbers.

Mathematics
1 answer:
Vlad [161]2 years ago
5 0

Answer:

3 5 -5 2 and 7 are the numbers

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Jefferson Middle School needs to see a 300% gain in PTO fundraiser
Ronch [10]

Given parameters:

Percentage gain = 300%

Selling cost last year = $2420

Unknown:

Selling cost this year  = ?

Solution:

To solve this problem;

     Profit percent  = \frac{Selling cost this year - Selling cost last year}{Selling cost last year} x 100

      300 = \frac{S - 2420}{2420}  x 100

      3 = \frac{S - 2420}{2420}

         S- 2420 = 7260

          S = $9680

To make a 300% gain, Jefferson Middle school needs a $9680 from fundraiser sales this year.

6 0
3 years ago
The base of a rectangular pyramid has dimensions 3 feet by 9 feet. The height of the pyramid is 11 feet.
AveGali [126]

Answer:

99

Step-by-step explanation:

1.  rectangular pyramid formula:

2.  V=lwh/3

3.  99 = (3)(9)(11)/3

5 0
3 years ago
Read 2 more answers
WHOEVER ANSWERS I WILL MARK BRAINLIEST
Gemiola [76]

Answer:

B

Step-by-step explanation:

Prime Factorization involves breaking down a number into prime numbers (aka numbers that can only be divided by itself and 1)

36

9  x  4

(3x3) x (2x2)

Hope that helps!

3 0
3 years ago
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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

6 0
3 years ago
Show that (2+3) + 6= (6+3) +2
lara [203]

Answer: use order of operstions

Step-by-step explanation:

4 0
2 years ago
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