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vazorg [7]
2 years ago
13

Look at this list of numbers.

Mathematics
1 answer:
Vlad [161]2 years ago
5 0

Answer:

3 5 -5 2 and 7 are the numbers

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Hallar el area de un triangulo equilatero cuyas bases miden 70dm y 134 dm y el lado oblicuo 85dm
Novay_Z [31]
Honestly I don’t know the answer I tried
4 0
3 years ago
Plz help on #7&10 just explain how to solve the question plz this is due tomorrow plz help
Colt1911 [192]
#7 is 14 becuse 7 goes into a hundred 14 times #10 is 28 cause 28 goes into 255 9 times
8 0
3 years ago
Read 2 more answers
It costs $10 per person to enter the museum. How much money would it cost for 30 people to enter the museum?​
Iteru [2.4K]

Answer:

The answer is 300

Step-by-step explanation:

Just multiply 10 by 30.

8 0
3 years ago
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The DiMonte Corporation invented a new type of sunglass lens. Their variable expenses are $12.66 per unit, and their fixed expen
Sladkaya [172]

Answer:

a)one lens: 111,212.66

15000 lenses: 301,100

b)y=111,200+12.66x

slope: 12.66

c)12.66 dollars per unit of lens produced

d) 20.07

e) 19.2

f)decreases

Step-by-step explanation:

a) Cost of producing one lens

fixed expenses+variable expenses=111,200+12.66=111,212.66

Cost of producing 15,000 lenses

fixed expenses+variable expenses=111,200+12.66(15,000)=301,100

b)Expense function:

let y be the expense cost

let x be the number of lenses produced

y=111,200+12.66x

Slope:

The function is  a line equation: y=mx+b where m is the slope.

In this case b=111,200 and m=12.66. So the slope is 12.66

c) the cost increases 12.66 dollars per unit of lens produced

d) The cost of producing 15000 lenses is:

111,200+12.66(15,000)=301,100

If DiMonte produces 15000 lenses, the average cost per lens is:

301,100/15000=20.073≈20.07

e)The cost of producing 17000 lenses is:

111,200+12.66(17,000)=326,420

If DiMonte produces 17000 lenses, the average cost per lens is:

326,420/17,000=19.2

f)The average per lens decrease.

8 0
3 years ago
*HELP PLEASE*
aksik [14]
If two events are disjoint (i.e. mutually exclusive) they cannot both occur and so we can determine probabilties by simple addition:

P(AorB)=P(A)+P(B) 
P(AorB)=\frac{40}{61}+\frac{2}{61} 
P(AorB)=\frac{42}{61} 
P(AorB)\approx 68.8\% 

A more complete answer would use a joint probability table but that's difficult to type out/format correctly here. 
7 0
3 years ago
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