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umka2103 [35]
3 years ago
6

What is the circumference of this circle?

Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0

Answer:

18.16 km

Step-by-step explanation:

r = 2km so i took each circle there is 4 circle's and i multiplied each circle by 2 that's how i got the answer -.-

Roman55 [17]3 years ago
6 0

Answer:

12.56 km

Step-by-step explanation:

It's 12.56 km because the radius is 2 km, so...

2 * 2=4

(because that is just half)

4 * pi = 12.56

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Deisha can build a fence in 15 hours, and Travis can build a fence in 12 hours. How long will it take them together to build a f
Basile [38]

Answer:

6\frac{2}{3}

Step-by-step explanation:

Deisha's build rate = 1 fence per 15 hours = 1/15 fences per hour

Travis's build rate = 1 fence per 12 hours = 1/12 fences per hour

Working together, their combined rate is 1/15 + 1/12 = 3/20 fences per hour

So it takes them 20/3 = 6 2/3 hours per fence

6 0
3 years ago
Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box
pantera1 [17]
To find the z-score for a weight of 196 oz., use

z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2.  Carl is wondering about the percentage of boxes with weights ABOVE z = 2.  The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0
3 years ago
Janelle ate 82% of the pie. What fraction of the pie remained? help meee
pav-90 [236]

Answer:

There is 18% left of the pie.

Step-by-step explanation:

There is only 100% of a pie. If she at 82% then there is 18% left. 100-82=18

4 0
3 years ago
Read 2 more answers
Solve the following equation:
Rama09 [41]

Complete the square.

z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0

\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4

Use de Moivre's theorem to compute the square roots of the right side.

w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)

\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2

Now, taking square roots on both sides, we have

z^2 + \dfrac12 = \pm w^{1/2}

z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2

Use de Moivre's theorem again to take square roots on both sides.

w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)

\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}

w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)

\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}

3 0
2 years ago
Please help me with this​
Lelu [443]

Answer:

D

Step-by-step explanation:

DDDDdDDDD

3 0
3 years ago
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