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Margarita [4]
2 years ago
7

Is 1/2(2p+9)=-p+5 a one solution or infinite solution or no solution​

Mathematics
1 answer:
vitfil [10]2 years ago
4 0

Your inequality has one solution which is p = 1/4

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X + (2x + 40) + (3x – 50) = 15,002
Charra [1.4K]

Answer:

2497.22...

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Step 3: 2x > 10 Step 4: x > 5 What property justifies the work between step 3 and step 4? A. division property of inequali
BigorU [14]

Answer:

A. Division property of inequality.

Step-by-step explanation:

Let be 2\cdot x > 10, we proceed to show the appropriate procedure to step 4:

1) 2\cdot x >10 Given

2) x > 5 Compatibility with multiplication/Existence of multiplicative inverse/Associative property/Modulative property/Result. (Division property of inequality)

In consequence, the division property of inequality which states that:

\forall\, a, b, c \in \mathbb{R}. If c > 0, then:

a> b\,\longrightarrow a\cdot c > b\cdot c \,\lor\, a

But if c < 0, then:

a> b\,\longrightarrow a\cdot c < b\cdot c \,\lor\, a b\cdot c

Hence, correct answer is A.

5 0
3 years ago
Tentukan mean, median, dan modus dari 7,4,5,6,7,4,5,7,8,9, dan 6
Anvisha [2.4K]

Answer:

<h3>Median = 6</h3><h3>Mean = 6,1</h3><h3>Modus = 7</h3>

Step-by-step explanation:

Median (Nila tengah setelah data diurutkan)

= 4, 4, 5, 5, 6, 6, 7, 7, 7, 8, 9

= 6

Mean

= jumlah data / banyak data

= 4+4+5+5+6+6+7+7+7+8+9/11

= 68/11

= 6,1

Modus

= data yang paling banyak muncul

= 7 (muncul sebanyak 3 kali)

3 0
3 years ago
A​ ​piece​ ​of​ ​rope​ ​94.2​ ​inches​ ​long​ ​will​ ​enclose​ ​a​ ​circular​ ​child’s​ ​wading pool. What​ ​is​ ​the​ ​diameter
Elis [28]
The circumference of a circle is pi times D. So, 94.2/pi = 29.98 or about 30 in
4 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
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