Answer:
2497.22...
Step-by-step explanation:
Answer:
A. Division property of inequality.
Step-by-step explanation:
Let be 
, we proceed to show the appropriate procedure to step 4:
1) 
Given
2) 
Compatibility with multiplication/Existence of multiplicative inverse/Associative property/Modulative property/Result. (Division property of inequality)
In consequence, the division property of inequality which states that:
. If 
, then:
But if 
, then:
Hence, correct answer is A.
Tentukan mean, median, dan modus dari 7,4,5,6,7,4,5,7,8,9, dan 6
Anvisha [2.4K]
Answer:
<h3>Median = 6</h3><h3>Mean = 6,1</h3><h3>Modus = 7</h3>
Step-by-step explanation:
Median (Nila tengah setelah data diurutkan)
= 4, 4, 5, 5, 6, 6, 7, 7, 7, 8, 9
= 6
Mean
= jumlah data / banyak data
= 4+4+5+5+6+6+7+7+7+8+9/11
= 68/11
= 6,1
Modus
= data yang paling banyak muncul
= 7 (muncul sebanyak 3 kali)
The circumference of a circle is pi times D. So, 94.2/pi = 29.98 or about 30 in
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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